Daughters get one X gene from each parent.
If the father is a normal male, he carries only a normal X-gene.
Therefore the daughter will always get a normal gene from the father, and a 50% probability getting an affected gene from the mother, therefore 50% chance of becoming a carrier. The other 50% she will inherit a normal X-gene from each parent, thus a healthy female.
In conclusion, no daughter will have haemophilia from a carrier mother and a normal male.
(however, sons will have a 50% chance of inheriting affected X-gene and hence will have haemophilia).
Answer:
20 molecules of ATP
Explanation:
Krebs cycle or also known as Tricarboxylic acid cycle (TCA) is the second stage of aerobic cellular respiration which occurs in the mitochondria. In the kreb cycle, pyruvate, which was synthesized in the first stage of cellular respiration (glycolysis) is broken down into carbon dioxide (CO2).
However, in the krebs cycle, two (2) ATP molecules is produced per glucose molecule that enters cellular respiration. Hence, according to this question, If 10 glucose molecules enter the Krebs cycle, (2 × 10) = 20ATP molecules will be possibly produced.
Primary
Secondary
Trinary
Quarternary
Hydrogen bonds remains
Answer:
Yellow seed colour (heterozygous)
Explanation:
Since we are performing experiment on the garden pea, so in the garden pea Yellow seed color is dominant and green one is recessive.
The allele responsible for the seed colour is denoted by Y.
So,
Homozygous parent having Yellow seeds will have allelic configuration as YY and the other homozygous parent with green seeds will have yy as pair of alleles.
In the cross of YY × yy the F1 progeny will be Yy which means F1 offspring will will be heterozygous and have Yellow seed colour because Yellow seed colour is dominant over the green colour. Green colour will express itself only in the homozygous condition.
