A 1-pound box of candy cost $4.00. What was the cost<br> per ounce (1 pound 16 ounces)?

Find the cosine ratio of angle ?. hint: use the slash symbol ( / ) to represent the fraction bar, and enter the fraction with no

Andru [333]

We are given that the angle a is the right angle. So let us work from this.

ab = 12 (the vertical side of the triangle)

bc = 13 (which if drawn can be clearly observed to be the hypotenuse) = the side opposite to angle a

ca = 5 (the horizontal side of the triangle)

Since we are to find for the cosine ratio of angle c or angle θ, therefore:

cos θ = adjacent side / hypotenuse

cos θ = ca / bc

cos θ = 5 / 13

Check out the attached image below for the illustration of the triangle.

6 0

4 years ago

One year Perry had the lowest ERA (earned-run average, mean number of runs yielded per nine innings pitched) of any male pitch

Blizzard [7]

Answer:

z score Perry $z=-1.402$

z score Alice $z=-1.722$

Alice had better year in comparison with Perry.

Step-by-step explanation:

Consider the provided information.

One year Perry had the lowest ERA of any male pitcher at his school, with an ERA of 3.02. For the males, the mean ERA was 4.206 and the standard deviation was 0.846.

To find z score use the formula.

$z=\frac{x-\mu}{\sigma}$

Here μ=4.206 and σ=0.846

$z=\frac{3.02-4.206}{0.846}$

$z=\frac{-1.186}{0.846}$

$z=-1.402$

Alice had the lowest ERA of any female pitcher at the school with an ERA of 3.16. For the females, the mean ERA was 4.519 and the standard deviation was 0.789.

Find the z score

where μ=4.519 and σ=0.789

$z=\frac{3.16-4.519 }{0.789}$

$z=\frac{-1.359}{0.789}$

$z=-1.722$

The Perry had an ERA with a z-score is –1.402. The Alice had an ERA with a z-score is –1.722.

It is clear that the z-score value for Perry is greater than the z-score value for Alice. This indicates that Alice had better year in comparison with Perry.

7 0

3 years ago

The coordinates of the vertices of triangle ABC are A(3,6), B(6, 3), and C(9, 9). If triangle ABC Is dilated by 1/3x and 1/3y to

katovenus [111]

Answer:

$A' = (1,2)$