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3 years ago

A 1-pound box of candy cost $4.00. What was the cost per ounce (1 pound 16 ounces)?

Mathematics

1 answer:

vodka [1.7K]3 years ago

5 0

Answer:

I think its $1 every 4 oz

Step-by-step explanation:

Basing this off that 4 * 4 is 16

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The diagram below shows a square cardboard with an area of 132.25 cm ².A square of side x cm is cut and removed from each of its

PilotLPTM [1.2K]

Answer:

i think it's 10.6

Step-by-step explanation:

112 = x^2

4 0

3 years ago

On one day, 4 chefs and 5 helpers earned $650.

Arlecino [84]

4c + 5h = 650 and

5c + 6h = 800 where c are chefs, h are helpers

Start by finding an expression for c

4c + 5h = 650
4c = 650 -5h
c = (650- 5h)/4

Then substitute that into the second equation and solve for a number value for h
5 (650-5h)/4 + 6h = 800
(3250-25h)/4 + 6h = 800
Multiply both sides by 4
3250-25h + 24h = 3200
-h = -50
h = 50

Take that 50 and substitute it into the expression we have for c to get a number value for c

C= 650-5(50)/4
C = 650-250/4
C = 400/4
C= 100

Check your first equations, substituting $50 for the helpers and $100 for the chefs.

4 (100) + 5(50) =
400 + 250 = 650

5(100) + 6(50) =
500 + 300 = 800

6 0

3 years ago

Triangle ABC is reflected to form Triangle A’B’C

SVEN [57.7K]

Answer:

I believe it is reflection across the x axis.

Callie

P..S Are you in k12

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

A box contains five keys, only one of which will open a lock. Keys are randomly selected and tried, one at a time, until the loc

Schach [20]

Answer:

Step-by-step explanation:

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3 years ago

Almost all medical schools in the United States require students to take the Medical College Admission Test (MCAT). To estimate

yKpoI14uk [10]

Answer:

a) 0.5588

b) 0.9984

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 24

Standard Deviation, σ = 6.4

We are given that the distribution of score is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) P(score between 20 and 30)

$P(20 \leq x \leq 30) = P(\displaystyle\frac{20 - 24}{6.4} \leq z \leq \displaystyle\frac{30-24}{6.4}) = P(-0.62 \leq z \leq 0.94)\\\\= P(z \leq 0.94) - P(z < -0.62)\\= 0.8264 - 0.2676 = 0.5588 = 55.88\%$

$P(20 \leq x \leq 30) = 55.88\%$

b) Sampling distribution

Sample size, n = 22

The sample will follow a normal distribution with mean 24 and standard deviation,

$s = \dfrac{\sigma}{\sqrt{n}} = \dfrac{6.4}{\sqrt{22}} =1.36$

c) P(mean score of sample is between 20 and 30)

$P(20 \leq x \leq 30) = P(\displaystyle\frac{20 - 24}{1.36} \leq z \leq \displaystyle\frac{30-24}{1.36}) = P(-2.94 \leq z \leq 4.41)\\\\= P(z \leq 4.41) - P(z < -2.94)\\= 1 - 0.0016 = 0.9984 = 99.84\%$

$P(20 \leq x \leq 30) =99.84\%$

5 0

3 years ago