Answer:
B. the atomic weight of the element
Explanation:
since it talks about mass i think weight
The exact answer is 145000
Answer:
Average atomic mass = 6.96 amu.
Explanation:
Abundance of Li-6 = 4%
Abundance of Li-7 = 96%
Atomic mass of Li-6 = 6 amu
Atomic mass of Li-7 = 7 amu
Average atomic mass = ?
Solution:
Average atomic mass = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass) / 100
Average atomic mass = (4×6)+(96×7) /100
Average atomic mass = 24 + 672 / 100
Average atomic mass = 696 / 100
Average atomic mass = 6.96 amu.
<h3>
Answer:</h3>
0.130 moles NH₃
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<u>Stoichiometry</u>
- Using Dimensional Analysis
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
[Given] 7.85 × 10²² molecules NH₃
[Solve] moles NH₃
<u>Step 2: Identify Conversions</u>
Avogadro's Number
<u>Step 3: Convert</u>
- [DA] Set up:

- [DA] Multiply/Divide [Cancel out units]:

<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
0.130355 moles NH₃ ≈ 0.130 moles NH₃
Prokaryotes undergo an aerobic respiration, pyruvate oxidation and the Krebs cycle take place in the cytoplasm since they do not have mitochondria.