Answer: = 3.11 x 10^14 s^-1
Explanation:
Use the formula E = hv
This formula uses the assumption that the unit for energy is in Joules/photon.
124 kJ = 124000J
To get 124000J/mol into a unit of J/photons, we need to divide by the number of photons in a mole, which is 6.022 x 10^23.
And thus, we need
124000/6.022 x 10^23 = 2.06 x 10^-19J/photon
We can plug it in to E = hv by
2.06 x 10^-19J = (6.63 x 10^-34 J s)(v) Isolate v by
v = (2.06 x 10^-19J)/(6.63 x 10^-34 J s)
= 3.11 x 10^14 s^-1
Answer:
[CO] = 0.078M
[Cl2] = 0.078M
[COCl2] = 0.477M
Explanation:
Based on the reaction:
CO(g) Cl2(g) ⇄ COCl2(g)
<em>Where equilibrium constant, kc, is:</em>
kc = 77.5 = [COCl2] / [CO] [Cl2]
[] represents the equilibrium concentration of each gas. The initial concentration of each gas is:
[CO] = 0.555mol/1.00L = 0.555M
[Cl2] = 0.555M
And equilibrium concentrations are:
[CO] = 0.555M - x
[Cl2] = 0.555M - x
[COCl2] = x
<em>Where x is reaction coordinate</em>
Replacing in kc expression:
77.5 = [x] / [0.555M - x] [0.555M - x]
77.5 = x / 0.308025 - 1.11 x + x²
23.8719 - 86.025 x + 77.5 x² = x
23.8719 - 87.025 x + 77.5 x² = 0
x = 0.477M. Right answer
x = 0.646M. False answer. Produce negative concentrations
Replacing:
<h3>[CO] = 0.555M - 0.477M = 0.078M</h3><h3>[Cl2] = 0.078M</h3><h3>[COCl2] = 0.477M</h3>
And those concentrations are the equilibrium concentrations
The chemical properties of an element are largely determined by its <span>number of valence electrons. The answer is letter D. The rest of the choices do not answer the question above.</span>
Answer:
3.4225 * 10^-8
Explanation:
This is just another way to write a number in scientific notation.
