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umka21 [38]
3 years ago
7

Classify the following triangle. check all that apply.

Mathematics
2 answers:
podryga [215]3 years ago
5 0

Answer:

Scalene and acute

Step-by-step explanation:

Mrrafil [7]3 years ago
4 0
Scalene and acute is the answers
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4x^2=27x+40<br> Solve by factoring
worty [1.4K]

Answer: hewo, there! your answer is below

x= -5/4

or x= 8

Step-by-step explanation:

step 1: Subtract 27x+40 from both sides.

4x2−(27x+40)=27x+40−(27x+40)

4x2−27x−40=0

Step 2: Factor left side of equation.

(4x+5)(x−8)=0

Step 3: Set factors equal to 0.

4x+5=0 or x−8=0

hope this helps you

have a great Day

Plz makr branilest

8 0
3 years ago
Which is the approximate solution to the system y = 0.5x + 3.5 and y = − 2/3 x + 1/3 shown on the graph? (–2.7, 2.1) (–2.1, 2.7)
AlekseyPX

Answer:

The approximate solution to the system is (-2.7, 2.1).

Step-by-step explanation:

To solve the system of equations \begin{bmatrix}y=0.5x+3.5\\ y=-\frac{2}{3}x+\frac{1}{3}\end{bmatrix} you must:

\mathrm{Rationalize\:equations}\\\\\begin{bmatrix}y=\left(\frac{1}{2}\right)x+\left(\frac{7}{2}\right)\\ y=-\frac{2}{3}x+\frac{1}{3}\end{bmatrix}

\mathrm{Subsititute\:}y=-\frac{2}{3}x+\frac{1}{3}\\\\\begin{bmatrix}-\frac{2}{3}x+\frac{1}{3}=\frac{1}{2}x+\frac{7}{2}\end{bmatrix}

\mathrm{Isolate}\:x\:\mathrm{for}\:-\frac{2}{3}x+\frac{1}{3}=\frac{1}{2}x+\frac{7}{2}\\\\-\frac{2}{3}x=\frac{19}{6}+\frac{1}{2}x\\\\-\frac{7}{6}x=\frac{19}{6}\\\\6\left(-\frac{7}{6}x\right)=\frac{19\cdot \:6}{6}\\\\-7x=19\\\\x=-\frac{19}{7}\approx-2.7

\mathrm{For\:}y=-\frac{2}{3}x+\frac{1}{3}\\\\\mathrm{Subsititute\:}x=-\frac{19}{7}\\\\y=-\frac{2}{3}\left(-\frac{19}{7}\right)+\frac{1}{3}\\\\y=\frac{15}{7}\approx 2.1

The approximate solutions to the system of equations are:

x=-2.7 ,\:y=2.1

5 0
3 years ago
Read 2 more answers
Look at the picture ASAP
goldenfox [79]
Using the Laws of Cosine, we obtain C^2 = 55^2+108^2-2(108)(55)*cos(59), which c approximately equals 153.44. So Line AB ≈ 153.44 meters.  
8 0
3 years ago
Complete the identity, sin(a+b)/cosacosb=​
8090 [49]

Answer:

tana + tanb

Step-by-step explanation:

Using the trigonometric identities

• sin(a + b) = sinacosb + cosasinb

• tanx = \frac{sinx}{cosx}, then

\frac{sin(a+b)}{cosacosb}

= \frac{sinacosb+cosasinb}{cosacosb}

= \frac{sinacosb}{cosacosb} + \frac{cosasinb}{cosacosb}

= \frac{sina}{cosa} + \frac{sinb}{cosb}

= tana + tanb

5 0
3 years ago
Which point is a solution to the system of inequalities below?
grin007 [14]

Answer:

(4, 3)

Step-by-step explanation:

It is the only one of those points that is in the purple section, which is the solution area

5 0
2 years ago
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