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Katyanochek1 [597]
3 years ago
11

KCIO3(s) → KCl(s) + O2(g) in word equation

Chemistry
1 answer:
vodomira [7]3 years ago
4 0
What? I can’t understand
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Sample of 200mls of 0.5 sulphuric acid,was asked to produce 1.2M of the new solution.Calculate the volume of the new solution​
uysha [10]

Answer: The volume of the new solution​ is 83.33 mL.

Explanation:

Given: V_{1} = 200 mL,    M_{1} = 0.5 M

V_{2} = ?,             M_{2} = 1.2 M

Formula used to calculate the volume of new solution is as follows.

M_{1}V_{1} = M_{2}V_{2}

Substitute the values into above formula as follows.

M_{1}V_{1} = M_{2}V_{2}\\0.5 M \times 200 mL = 1.2 M \times V_{2}\\V_{2} = 83.33 mL

Thus, we can conclude that volume of the new solution​ is 83.33 mL.

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Juanita dissolves 46 g of MgBr2 (molar mass: 184.11 g/mol) in 0.5 kg of distilled water. What is the molality of the solution?
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Formula: molality, m = n solute / kg solvent

n solute = # of moles of solute = mass(g) / molar mass

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m = [46g / 184.11 g/mol] / 0.5 kg = 0.50 mol/kg
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