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Sidana [21]
3 years ago
9

Sample of 200mls of 0.5 sulphuric acid,was asked to produce 1.2M of the new solution.Calculate the volume of the new solution​

Chemistry
1 answer:
uysha [10]3 years ago
5 0

Answer: The volume of the new solution​ is 83.33 mL.

Explanation:

Given: V_{1} = 200 mL,    M_{1} = 0.5 M

V_{2} = ?,             M_{2} = 1.2 M

Formula used to calculate the volume of new solution is as follows.

M_{1}V_{1} = M_{2}V_{2}

Substitute the values into above formula as follows.

M_{1}V_{1} = M_{2}V_{2}\\0.5 M \times 200 mL = 1.2 M \times V_{2}\\V_{2} = 83.33 mL

Thus, we can conclude that volume of the new solution​ is 83.33 mL.

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Question 39 (1 point)
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Answer:

volume = 2128L

Explanation:

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CO2 = 12 + 2(16) = 44

4.20/44 = volume/22400L

0.095 = volume/22400L

volume = 0.095 x 22400

volume = 2128L

5 0
3 years ago
When you heat a 50.0 L cylinder containing 10.0 moles of oxygen to 333 K, what is the pressure inside? (Use the ideal gas law PV
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3 years ago
You are given 10.00 mL of a solution of an unknown acid. The pH of this solution is exactly 2.95. You determine that the concent
Naily [24]

Answer:

1.038\times 10^{-5} is dissociation constant and the value of pK_a is 4.98.

Explanation:

The pH of the solution = 2.95 M

pH=-\log[H^+]

2.95=-\log[H^+]

[H^+]=10^{-2.95}=0.001122 M..[1]

Concentration of unknown monoprotic acid = C = 0.1224 M

HA\rightleftharpoons A^-+H^+

Initially

C                  0         0

At equilibrium

(C-x)              x         x

The expression of a dissociation reaction can be written as;

K_a=\frac{[A^-][H^+]}{[HA]}

K_a=\frac{x^2}{(C-x)}

[H^+]=x =0.001122 M  ( from [1])

K_a=\frac{(0.001122 M)^2}{(0.1224 M-0.001122 M)}

K_a=1.038\times 10^{-5}

The value of pK_a :

pK_a=-\log[K_a]

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1.038\times 10^{-5} is dissociation constant and the value of pK_a is 4.98.

8 0
3 years ago
Is h20 polar or non polar
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Explanation:

3 0
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In the nucleus, a sodium atom (Na) has 11p+ and 12 nºo. How would you write the
Hatshy [7]

Answer:

Na⁺

Explanation:

Given parameters:

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Writing the expression based on sodium ion that lost one electron;

In a neutral sodium atom, the number of protons and electrons are the same. Number of protons are the the positively charged particles in an atom.

Number of electrons are the negatively charged particles.

If an atom loses electron for instance sodium:

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           Number of protons  = 11

Charge on the atom  = 11  - 10  = 1+

So, the symbol of the atom is Na⁺

4 0
3 years ago
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