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ella [17]
3 years ago
9

Think of an example in which chemical and physical weathering affects a rock

Chemistry
1 answer:
lara31 [8.8K]3 years ago
5 0

Answer:

chemical-Acid rain eating away at the rock

Physical-Dust particles eroding the rock overtime in the wind

Explanation:

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Whats the name?!?!?!??!?!?!?!?!?!?!!?!?!?!??!?!?!?!
SIZIF [17.4K]
Hydrogen i suppose is the right one
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3 years ago
For two variables in a direct proportion, what is the result of doubling one variable?
Airida [17]

Answer:

the other variable is also doubled

Explanation:

direct proportion, same thing has to happen to both variables

6 0
3 years ago
Calculate the mean kinetic energy {e1rans) in joules of the following molecules at 350 k: (a) he, (b) co2, and (c) uf6. explain
Lady bird [3.3K]

The mean kinetic energy per molecule is , where  is the Boltzmann constant and T is the absolute temperature.

So at 1000°C, the T = 1273.15 K, kB=1.38 × 10-23, therefore the mean kinetic energy is 2.635 × 10⁻²⁰J.

<h3><u>What is Kinetic energy ?</u></h3>

The energy an item has as a result of motion is known as kinetic energy.

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Kinetic energy may be converted into other types of energy and transported between things. A flying squirrel may run into a chipmunk that is standing still, for instance. Some of the squirrel's original kinetic energy may have been transferred to the chipmunk or changed into another kind of energy after the impact.

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4 0
1 year ago
21. The formation of an ionic bond involves the a transfer of electrons. b. transfer of neutrons. c. transfer of protons. d. sha
iren2701 [21]

Answer:

I think its C but if its not try A then

Explanation:

7 0
2 years ago
12oz of water initially at 75oF is mixed with 20oz of water intiially at 140oF. What is the final temperature?
Kaylis [27]

Answer:

115.625^{\circ}\text{F}

Explanation:

m_1 = First mass of water = 12 oz

m_2 = Second mass of water = 20 oz

\Delta T_1 = Temperature difference of the solution with respect to the first mass of water = (T-75)^{\circ}\text{F}

\Delta T_2 = Temperature difference of the solution with respect to the second mass of water = (T-75)^{\circ}\text{F}

c = Specific heat of water

As heat gain and loss in the system is equal we have

m_1c\Delta T_1=m_2c\Delta T_2\\\Rightarrow m_1\Delta T_1=m_2\Delta T_2\\\Rightarrow 12(T-75)=20(140-T)\\\Rightarrow 12T-900=2800-20T\\\Rightarrow 12T+20T=2800+900\\\Rightarrow 32T=3700\\\Rightarrow T=\dfrac{3700}{32}\\\Rightarrow T=115.625^{\circ}\text{F}

The final temperature of the solution is 115.625^{\circ}\text{F}.

3 0
3 years ago
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