We are given with
dimensions of wheelbarrow = 2ft x 3ft x 1.5 ft
dimensions of truck = 11 ft x 8 ft x 6 ft
The volume of the wheelbarrow is 2(3)(1.5) = 9 ft3
The volume of the truck is 11(8)(6) = 528 ft3
70% of this is
528 ft3 (0.7) = 369.6 ft3
Dividing this by the volume of the wheelbarrow
369.6 ft3 / 9 ft3 = 41.07
He would need to use the wheelbarrow 42 times.
Answer:
steps below
Step-by-step explanation:
Total = 12+17+14 = 43
Without replacement:
C(12,5) / C(43,5) = (12!/5!*7!) / (43!/5!*38!) = (12*11*10*9*8) / (43*42*41*40*39)
= 95040 / 115511760
= 0.00082
≈ 0.082%
with replacement: 12/43*12/43*12/43*12/43*12/43 = 12⁵ / 43⁵
Area of triangles: 1/2 x b x h
area of square: l x w
Triangle
1/2 x 7 x 4= 14, but there are 3 of them so 42
Square: 7 x7 = 49
49 + 42 = 91
Answer:7
7
Step-by-step explanation:
0.83 * 100 = 83, so 0.83 = 83/100.
But in case you meant the slightly more interesting repeating decimal, 0.8333...:
Let <em>x</em> denote this number. Then
10<em>x</em> = 8.333...
100<em>x</em> = 83.333...
==> 100<em>x</em> - 10<em>x</em> = 83.333... - 8.333...
==> 90<em>x</em> = 83 - 8 = 75
==> <em>x</em> = 75/90 = 5/6
