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Andrei [34K]
3 years ago
13

Please!!!!!! Answer These Plato Composites of Inverse Functions

Mathematics
2 answers:
Neko [114]3 years ago
5 0
Hope this helps bye bye thanks
Archy [21]3 years ago
3 0
What’s the question you need help on?
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Help?,?,?,?.!.??.?.?.?.?.?.
DaniilM [7]

Answer:

Step-by-step explanation:

b(a + 1) + a = b*a + b + a = ab + b + a

1) b(2a +1 ) = b*2a + b*1 = 2ab + b  Not equivalent.

2)a + (a +1)*b = a + ab+ b     Equivalent

3) (a +1)(b+ a) = a*(b +a) + 1*(b+a) = ab+ a² +b + a  Not equivalent.

4) (a + 1)b + a = ab+ b + a   Equivalent

5) a + b(a+1) = a +ab + b Equivalent

6) a + (a +1) + b = a + a + 1 + b = 2a + 1 +b  Not equivalent.

7) a(b +1) + b = ab + a + b  Equivalent

5 0
3 years ago
Bob gets paid an annual salary of $30,000 and earns 5% commission on all sales he makes. If Bob wants to make $6,000 this month,
Evgesh-ka [11]

Answer:

if Bobs want to make $6000 commission he needs to make $120,000 sales.

*choices d

Step-by-step explanation:

in $3000, the 5% of Bobs commission is $150

*solution

5% is equivalent to 0.05 in decimal

3000 × 0.05 = 150

so just divide the 5% to $6000 to get the sales

*solution

$6000 ÷ 0.05 = $120,000

6 0
3 years ago
Read 2 more answers
I finished question 1 but I could use some help on the others​
Eddi Din [679]

Answer:

With the first four questions, all you need to do is find a value of x that gives you a zero value in any one of those brackets.  Let's do it.

You said you finished 1, so let's skip it.

I can't give you a full answer for question 2, because you didn't capture the entire expression in the screenshot.  I can see that the values 3 and 0.125 would give zero values, but I can't tell you the last.

For question three, we need to find x values where either 9x + 3 = 0, or x² - 9 = 0.  There are three values that meet those conditions.  You can solve it just by assigning a zero value and solving for x:

9x + 3 = 0\\3x + 1 = 0\\3x = -1\\x = -1/3

For the second term actually has two solutions, because a squaring a number also causes negatives to be converted to positives.  Another way of seeing this is to notice that the second term is actually a difference of squares:

p(x) = (9x + 3)(x^2 - 9)\\= (9x + 3)(x + 3)(x - 3)

so in this case x could be -1/3, -3, or 3 to give a zero value.

For question four, you can only get a zero if you use imaginary numbers, as no real number can be squared to give you a negative.  So the only answers to that are 5i, or -5i.

With questions five six seven and eight, we just need to make exceptions for zero denominators, so:

For question 5, you can x can be any real number except -4, 2 and 7

For 6, x can be anything but 3, 1/8th or 5

for 7, We again have that difference of squares, so the actual denominator is (9x + 3)(x + 9)(x - 9), meaning x can be anything but -1/3, -9, or 9

And finally for question 8, we again have a squaring, meaning that only an imaginary number will cause division by zero, meaning x can't be 5i or -5i.

7 0
3 years ago
A standard number cube is tossed. find p(even or prime).
BlackZzzverrR [31]
The correct answer is: P(even or prime) = 5/6

Explanation:

First the P(E) = Probability of Even = 3/6 = 1/2 (because 2,4,6 are even numbers)
P(p) = Probability of Prime = 3/6 = 1/2 (because 2,3,5 are the prime numbers)

Now
P(even AND prime) = 1/6 (because 2 is not only an even number but also the prime number)

Hence
P(even or prime) = P(E) + P(p) - P(even AND prime) = 1/2+1/2 -1/6 = 5/6
5 0
3 years ago
Read 2 more answers
Jevon has joined a gym. The membership has an initial fee of $50.00 and costs $10.00 per month
Alenkinab [10]

Answer:   Months, x : 15      Total cost, y:  $150.00  and $250.00

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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