Since the common difference is 6, we can assume that the sequence is arithmetic, with rule
T(n)=6n+5 where T(1)=11
T(9)=6(9)+5=59
7/8 and 9/16
7*2/8*2 = 14/16
14/16 and 9/16
Now since we have a common denominator, we can compare the numerators.
14/16 is greater, so 7/8 is greater than 9/16
Answer: 7/8 is bigger
Answer:
there are 11 diffrent sums and the greatest sum is 12
Step-by-step explanation: