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lozanna [386]
3 years ago
5

On a scale from -5 to 5 which numbers are smaller than 2

Mathematics
2 answers:
Anestetic [448]3 years ago
5 0

Answer:

1, 0, -1, -2, -3, -4, -5

Step-by-step explanation:

zlopas [31]3 years ago
4 0

Answer:

The answer is -5, -4, -3, -2, -1, 0, 1.

Step-by-step explanation:

Because they are behind the number 2

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Help me please<br> Solve the system algebraically using substitution.
cluponka [151]

Answer:

y = 5/3

x = 8/3

Steps:

y = x - 1

2x + y = 7

Substitute y = x-1

(2x + x - 1 = 7)

Simplify: 3x - 1 = 7

Isolate x: 3x - 1 = 7:  x=8/3

Plug the valuse of x into the other equation (y = x- 1):    y = 8/3 - 1

8/3 - 1 = 5/3

y = 5/3

y = 5/3, x = 8/3

3 0
3 years ago
Will give brainliest to correct answer.
Kobotan [32]
Note that c is the hypotenuse of the blue triangle, and that the Pyth. Thm. states that (length of one leg)^2 + (length of the other leg)^2 = (hyp)^2.

Therefore, (hyp)^2 = c^2 = [2sqrt(x^2+3x)]^2 + 3^2, or
                                        = 4(x^2+3x) + 9, or
                                        = 4x^2 + 12x + 9  = (2x+3)^2
Taking the sqrt of both sides, c = plus or minus (2x+3).  Eliminate -(2x+3) because the middle term of the square of this would be negative, in conflict with the given +12x.

c=2x+3 is the correct answer.

8 0
3 years ago
What is one third of 1296?
Kryger [21]

Answer:

four hundred thirty-two

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Help pls :’( ASAPP!!!<br> “Complete the proof”
nata0808 [166]

1) \overline{AB} \cong \overline{CD}, \overline{AD} \cong \overline{CB}, \overline{AX} \perp \overline{BD}, \overline{CY} \perp\overline{BD} (given)

2) \overline{BD} \cong \overline{BD} (reflexive property)

3) \triangle ABD \cong \triangle ACDB (SSS)

4) \angle ADB \cong \angle CBY (CPCTC)

5) \angle CYB and \angle AXD are right angles (perpendicular lines form right angles)

6) \triangle CYB and \triangle AXD are right triangles (a triangle with a right angle is a right triangle)

7) \triangle AXD \cong \triangle CYB (HA)

8) \overline{AX} \cong \overline{CY} (CPCTC)

6 0
2 years ago
I need help I got this wrong
wlad13 [49]
<h2>Solution : </h2>

y = -2|x +1|

→ |x + 1| = -y/2

→ x+1 = y/2

and

x + 1 = -y/2

→ x + 1 belongs to R

→ x belongs to R

Domain = R

Range = y = -2(R)

→( -∞ , 0)

3 0
3 years ago
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