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stepladder [879]
3 years ago
6

Rectangle ABCD is rotated 95° about point Q to create rectangle A'B'C'D'.

Mathematics
1 answer:
Anettt [7]3 years ago
7 0

Answer:

12

Step-by-step explanation:

Since both rectangles are of the same dimensions, simply multiply the width of the first box(2) and the length of the second box(6) together(2*6 = 12)

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Verify that [tan(theta) + cot(theta)]^2 = sec^2(theta) + csc^2(theta)
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(tanθ + cotθ)² = sec²θ + csc²θ

<u>Expand left side</u>: tan²θ + 2tanθcotθ + cot²θ

<u>Evaluate middle term</u>: 2tanθcotθ = 2*\frac{sin\theta}{cos\theta}*\frac{cos\theta}{sin\theta} = 2

⇒ tan²θ + 2+ cot²θ

= tan²θ + 1 + 1 + cot²θ

<u>Apply trig identity:</u>  tan²θ + 1 = sec²θ

⇒ sec²θ + 1 + cot²θ

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3 years ago
How do you solve 40.25 divided by 0.5
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3 years ago
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Mademuasel [1]

1. discriminant = b^2 - 4ac = (-5)^2 - (4 x 1 x 7) = 25 - 28 = -3  [imaginary root]


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3. discriminant = (8)^2 - (4 x 16 x 1) = 64 - 64 = 0    [double root]


Read more on Brainly.com - brainly.com/question/1698047#readmore




hope it helps

4 0
2 years ago
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Answer:

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Step-by-step explanation:

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Answer:

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