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Gnoma [55]
3 years ago
6

The average test score of RSM students in September increased by 10%. In October it increased by another 15%. By what percent di

d the average score on the test increase during the two months?
Mathematics
2 answers:
Rzqust [24]3 years ago
4 0

Answer:

26.5%

Step-by-step explanation:

The answer is the same as what AnimeBrainly said, but 126.5% is the total amount, not the increase. 100% to 126.5% is a 26.5% increase.

Aneli [31]3 years ago
3 0
The Average test score start = 100%

It increases by 10%: 

100% = 1
10% = 0.10

1 x 0.10 = 0.1
1 + 0.1 = 1.1

It increases by another 15%

1.1 x 0.15 = 0.165
1.1 + 0.165 = 1.265
Remember to move the place value digit to the right two spaces to make it a percentage

126.5% increase is your answer

hope this helps
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2 years ago
“76 is 60% of what?” Help!
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126.67

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The store had a special on apples, 4 pounds for $2.80. The store's special on oranges was 3 pounds for $2.58. Which of the follo
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Find the volume of this object.
Tems11 [23]

Answer:

408 cm^3

Step-by-step explanation:

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7 0
1 year ago
Find the generating function for the sequence 1,1,1,2,3,4,5,6,....
marin [14]

Answer:

P(x)=\dfrac{1}{1-x}+\dfrac{x^3}{(1-x)^2} \quad \text{for} \mid x \mid < 1[/tex]

Step-by-step explanation:

The generating function of a sequence is the power series whose coefficients are the elements of the sequence. For the sequence

1,1,1,2,3,4,5,6,...

the generating function would be

P(x)=1+x+x^2+2x^3+3x^4+4x^5+5x^6+...\\

we can multiply P(x) by x to get

xP(x)=x+x^2+x^3+2x^4+3x^5+4x^6+...

Note that

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which for \mid x \mid < 1 can be rewritten as

(1-x)P(x)=1+\dfrac{x^3}{(1-x)} \quad \Rightarrow \\\\P(x)=\dfrac{1}{(1-x)}+\dfrac{x^3}{(1-x)^2}

8 0
3 years ago
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