Question

3. REI.b4_Part A. A toy cannon ball is launched on top of a platform. The

Answer 1

Answer:

The correct option is;

D. -8·t² + 18·t + 6 = 10

Step-by-step explanation:

The given equation of the height toy cannon launched on top of a platform is given as follows;

h(t) = -8·t² + 18·t + 6...(1)

Where "h" represents the height in meters, at time "t" seconds after the ball is launched

When the height is 10 meters, we can write as follows;

The height of the ball, h(t) = 10

Therefore, by substituting the value of h(t) in equation (1), h(t) = -8·t² + 18·t + 6, when h(t) = 10 we get;

-8·t² + 18·t + 6 = 10.