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NeTakaya
2 years ago
8

Please I need ASAP. First one to answer will get Brainyist.

Mathematics
2 answers:
sasho [114]2 years ago
5 0

Answer:

1, 2, 3, 4, 2

Rzqust [24]2 years ago
4 0

Answer:

I'm just here for my points sorry bro

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X-46=-15<br> what is x <br><br><br> i will give you brainly if you get it right
PilotLPTM [1.2K]
X=31

hope this helps!!
7 0
2 years ago
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You have 10 cups of a cleaning solution that is 10% white vinegar and 90% water. You want the mixture to be 50% white vinegar an
lisabon 2012 [21]
Let
x-->volume of white vinegar you need to add to the mixture (measured in cups)
<span>then
the amount of the pure vinegar in the mixture will be -----> (10*0.1 + x) cups
t</span>he volume of liquid will be ---------> 10 + x
the concentration equation is-------> [(10*0.1 + x)/(10+x)]=0.50<span>multiply both sides by (10+x) and then simplify

</span>(10*0.1 + x)=(10+x)*0.50-----------> 1+x=5+0.50x-------> 0.50x=4
x=8

the answer is 
<span>you need to add 8 of a cup of the pure vinegar to the mixture</span>
7 0
3 years ago
What is the greatest common factor<br> of 48 and 120?
Charra [1.4K]

Answer:

24

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
Etermine two pairs of polar coordinates for the point (2, -2) with 0° ≤ θ &lt; 360°.
Jet001 [13]

To convert from rectangular to polar we will use these 2 formulas:

r^2=x^2+y^2 and

tan\theta=\frac{y}{x}.

The r value found serves as the first coordinate in our polar coordinate, and the angle serves as the second coordinate of the pair. We are told to find 2. Since the r value will always be the same (it's the length of the hypotenuse created in the right triangle we form when determining our angle theta), the angle is what is going to be different in our coordinate pairs. We use the x and y coordinates from the given rectangular coordinate to solve for the r in both our coordinate pairs.

r^2=2^2+ -2^2 which gives us an r value of 2\sqrt{2}. That's r for both coordinate pairs. Now we move to the angle. Setting up according to our formula we have

tan\theta =\frac{-2}{2} =-1.

This asks the question "what angle(s) has/have a tangent of -1?". That's what we have to find out! Since the tangent ratio is y/x AND since it is negative, it is going to lie in a quadrant where x is negative and y is positive, AND where x is positive and y is negative. Those quadrants are 2 and 4. In QII, x is negative so the tangent ratio is negative here; in QIV, y is negative so the tangent ratio is negative here as well. Now, if we type inverse tangent of -1 into our calculators in degree mode, we get that the angle that has a tangent of -1 is -45. Measured from the positive x axis, -45 does in fact go into the fourth quadrant. However, since the inverse tangent of -1 is -45, we also have a 45 degree angle in the second quadrant. Those are reference angles, mind you. A 45 degree angle in QII has a coterminal angle of 135 degree; a 45 degree angle in QIV has a coterminal angle of 315. If you don't understand that, go back to your lesson on reference angles and coterminal angles to see what those are. So our polar coordinates for that rectangular coordinate are

(2\sqrt{2},135) and

(2\sqrt{2},315)

8 0
3 years ago
What are the cordinates of (x-8,y+2)
sasho [114]

Answer:

To plot  

(

x

−

8

,

y

+

2

)

, start at the origin

(

0

,

0

)

and move right

x

−

8

units and up

y

+

2

units.

(

x

−

8

,

y

+

2

)

Step-by-step explanation:

5 0
2 years ago
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