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3 years ago

MY

Mathematics

1 answer:

Pie3 years ago

4 0

Answer:

<B = 56.25°

Step-by-step explanation:

Reference angle = B

Hypotenuse = AB = 9

Adjacent = BC = 5

Applying trigonometric ratio:

$cos (B) = \frac{adj}{hyp}$

$cos (B) = \frac{5}{9}$

$B = cos^{-1}(\frac{5}{9})$

B = 56.25° (nearest hundredth)

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What is the value of x in the equation 6(x + 1) – 5x = 8 + 2(x - 1)?<br> OIT MT

Alexandra [31]

Answer:

x=0

Step-by-step explanation:

To solve, we need to get all the variables on one side of the equation, and all the numbers on the other

6(x + 1) – 5x = 8 + 2(x - 1)

First, distribute the 6 on the left

6*x+6*1 -5x=8 +2(x-1)

6x+6-5x=8+2(x=1)

Combine like terms on the left

(6x-5x)+6=8+2(x-1)

x+6=8+2(x-1)

Distribute the 2 on the right

x+6=8+2*x+2*-1

x+6=8+2x-2

Combine like terms on the right

x+6=2x+(8-2)

x+6=2x+6

Subtract x from both sides

6=x+6

Subtract 6 from both sides

x=0

Hope this helps! :)

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3 years ago

compared to last year, the population of Boom Town has increased by 10%. The population is now 6,600. What was the population la

Rufina [12.5K]

Answer:

Step-by-step explanation:

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2 years ago

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For the relation S:{(2,3),(−1,4), (1,6)}. a Find the domain. B. Find range

Rudik [331]

Answer:

domain: {2, -1, 1}

range: {3, 4 6}

Step-by-step explanation:

In the relation of the form (x,y)

Set of all possible value of X is called Domain

Set of all possible value of Y is called Range

To get a list of domain and range it is required to separate value of x and y

_________________________________

Relation given in the problem

S:{(2,3),(−1,4), (1,6)}

domain: {2, -1, 1}

range: {3, 4 6}

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3 years ago

What is the row echelon form of this matrix?

USPshnik [31]

The row echelon form of the matrix is presented as follows;

$\begin{bmatrix}1 &-2 &-5 \\ 0& 1 & -7\\ 0&0 &1 \\\end{bmatrix}$

<h3>What is the row echelon form of a matrix?</h3>

The row echelon form of a matrix has the rows consisting entirely of zeros at the bottom, and the first entry of a row that is not entirely zero is a one.

The given matrix is presented as follows;

$\begin{bmatrix}-3 &6 &15 \\ 2& -6 & 4\\ 1&0 &-1 \\\end{bmatrix}$

The conditions of a matrix in the row echelon form are as follows;

There are row having nonzero entries above the zero rows.
The first nonzero entry in a nonzero row is a one.
The location of the leading one in a nonzero row is to the left of the leading one in the next lower rows.

Dividing Row 1 by -3 gives:

$\begin{bmatrix}1 &-2 &-5 \\ 2& -6 & 4\\ 1&0 &-1 \\\end{bmatrix}$