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2 years ago

The quadrilateral ABCD has area of 58 in2 and diagonal AC = 14.5 in. Find the length of diagonal BD if AC ⊥ BD.

Mathematics

1 answer:

azamat2 years ago

4 0

Answer:

(look in the the Step by step)

Step-by-step explanation:

When the diagonals of a quadrilateral are perpendicular, the area of that quadrilateral is half the product of their lengths.

.. A = (1/2)*d₁*d₂

Substituting the given information, this becomes

.. 58 in² = (1/2)*(14.5 in)*d₂

.. 2*58/14.5 in = d₂ = 8 in

The length of diagonal BD is 8 in.

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3x over 2x-6 plus 9 over 6-2x

Mars2501 [29]

Answer: 3/2
Explanation:
3x/2x-6 + 9/6-2x
= 3x/2x-6 + 9/-(2x+6)
= 3x/2x-6 + -9/2x-6
= 3x/2x-6 - 9/2x-6
= 3x - 9/2x-6
= 3(x-3)/2(x-3) (cancel out x-3)
= 3/2

7 0

3 years ago

Read 2 more answers

a quadratic equation has a discriminant of 12. which could be the equation? a.0 = –x2 8x 2 b.0 = 2x2 6x 3 c.0 = –x2 4x 1 d.0 = 4

Norma-Jean [14]

Answer:

Option b which is $2x^2+6x+3=0$

Step-by-step explanation:

We have been given the discriminant 12

We have to choose the equation which will satisfy the given discriminant.

We will consider all the given equation one by one

First we will take option a which is $-x^2+8x+2=0$

Discriminant from the equation we will find by the formula

$D=b^2-4ac$

Here, a=-1,b=8 and c=2 on substituting the values we will get

$D=8^2-4(-1)(2)=72$

Hence, option a is incorrect.

Now, we will consider option b which is $2x^2+6x+3=0$

Here, a=2,b=6 and c=3 on substituting the values we get

$D=(6)^2-4(2)(3)=12$

Hence, option b is correct

Therefore, option b is the required answer.

8 0

2 years ago

Read 2 more answers

If AB is 12, what is the length of A'B'?

lukranit [14]

Triangles ABC and A'B'C are similar. This means that the corresponding sides are in the same ratio, in this case:

$\frac{BC}{B^{\prime}C}=\frac{AC}{A^{\prime}C}=\frac{AB}{A^{\prime}B^{\prime}}$

Replacing with data:

$\begin{gathered} \frac{9}{6}=\frac{12}{A^{\prime}B^{\prime}} \\ 9\cdot A^{\prime}B^{\prime}=12\cdot6 \\ A^{\prime}B^{\prime}=\frac{72}{9} \\ A^{\prime}B^{\prime}=8 \end{gathered}$

7 0

8 months ago

<img src="https://tex.z-dn.net/?f=x%3D-2%5C%5Cx%2B3y%3D4" id="TexFormula1" title="x=-2\\x+3y=4" alt="x=-2\\x+3y=4" align="absmid

Natali5045456 [20]

X + 3y -4 =0 or x=4 I think that’s the answer

4 0

2 years ago

Solve for m.t=mr^2/3

spin [16.1K]

t = mr^2/3

Divide both sides by r^2/3

m = t / r^2/3