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1 answer:
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Based on the above, the Triangle XYZ and ACB are known to be similar triangles since tanX = tanA = 5 over 2 and 5 tenths;
Hence:
- AC = 2 x XY
- CB = 2 x YZ
From the question given; Triangle XYZ is known to have been dilated by a scale factor of 2 to form a type of triangle known as triangle ACB, So therefore, XYZ and ACB are known to be the same or similar triangles.
Since Angles Y and C are known to both measure 90 degrees, and angles A and X are said to be congruent. Therefore:
tanX = tanA = 5 over 2 and 5 tenths
AC = 2 x XY
CB = 2 x YZ
For part B:
cosX=Base/Hypotenuse
cos A=AC/AB
AC = 2.05
AB = 5.59
Therefore, Based on the above, the Triangle XYZ and ACB are known to be similar triangles since tanX = tanA = 5 over 2 and 5 tenths;
Hence:
- AC = 2 x XY
- CB = 2 x YZ
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Answer:
Observe that if the vector is in W then it satisfies:
This means that each vector in W can be expressed as a linear combination of the vectors
Also we can see that those vectors are linear independent. Then the set
is a basis for W and the dimension of W is 2.