Two lines are parallel when their slopes are the same.
Let events
A=Nathan has allergy
~A=Nathan does not have allergy
T=Nathan tests positive
~T=Nathan does not test positive
We are given
P(A)=0.75 [ probability that Nathan is allergic ]
P(T|A)=0.98 [probability of testing positive given Nathan is allergic to Penicillin]
We want to calculate probability that Nathan is allergic AND tests positive
P(T n A)
From definition of conditional probability,
P(T|A)=P(T n A)/P(A)
substitute known values,
0.98 = P(T n A) / 0.75
solving for P(T n A)
P(T n A) = 0.75*0.98 = 0.735
The values of a and b equals 10
Answer:
Step-by-step explanation:
Applying logarithm rule
Log A - Log B= Log(A/B). Division rule
Now, Logx-log(x+13)=1
Log(x/(x+13))=1
Assume that the log is a natural log whose base is 10.
Then apply logarithm law
Log10 base 10=1
Comparing this to Log(x/(x+13))=1
This implies that
x/(x+13)=10
x=10(x+13)
x=10x+130
x-10x=130
-9x=130
x=130/-9
x=-14.444
