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bezimeni [28]
2 years ago
5

A school chorus has 45 sixth-grade students and 70 seventh-grade students. The music director wants to make groups of performers

, with the same combination of sixth- and seventh-grade students in each group. She wants to form as many groups as possible.
What is the largest number of groups that could be formed?
Mathematics
2 answers:
Fittoniya [83]2 years ago
5 0

5 groups with 9 sixth-grade students and 14 seventh-grade students in each.

---

hope it helps

stepladder [879]2 years ago
5 0
The music director can make 15 groups of performers with 6 sixth grade students and 5 seventh grade students in each group.
Step-by-step explanation:
A school chorus has 90 sixth-grade students and 75 seventh-grade students.
Factor these two numbers:

Find GCF(90,75):

Now,

Therefore, the music director can make 15 groups of performers with 6 sixth grade students and 5 seventh grade students in each group.
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Find the surface area of the cube shown.
Alja [10]

A=6a^2

A=6(5.5)^2

A=181.5

Hopefully I answered correctly.

8 0
3 years ago
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Graph the image of the figure after a dilation with a scale factor of 2 centered at (−2,−2). Use the Polygon tool to graph the q
kolbaska11 [484]

Answer:

  see below

Step-by-step explanation:

Every vertex moves twice as far from the center of dilation as it is in the pre-image.

Perhaps the easiest image point to find is the one at lower left. In the pre-image it is 2 units left of the center of dilation, so the image point will be 2×2 = 4 units left of the center of dilation. It will be located at (-6, -2).

Other points on the image can be found either by reference to the center of dilation, or by reference to known image points. For example, the next point clockwise is 1 left and 4 up in the pre-image, so will be 2 left and 8 up from (-6, -2) in the image. That is, the pre-image point (-5, 2) becomes image point (-8, 6). You will note that (-5, 2) is 3 left and 4 up from the center of dilation, and that (-8, 6) is 6 left and 8 up from the center of dilation (twice as far away).

5 0
3 years ago
Please help! I currently have a C- in Math and I need an A before summer
san4es73 [151]
Its 12. I hope I help
6 0
3 years ago
Read 2 more answers
Can anyone help me with this question please:
ladessa [460]
The problem is asking us to isolate B. The given equation is solved for P, and we need to rearrange it for B.

First we need to square both sides. This will cancel out the square root on the right side.

P^2 = E + A^2/B^2

Next, subtract E from both sides.

P^2 - E = A^2/B^2

Next we need to get the B^2 out of the denominator. Multiply both sides by B^2.

B^2(P^2 - E) = A^2

Next divide both sides by (P^2 - E).

B^2 = A^2/(P^2 - E)

Lastly, take the square root of both sides.

B = sqrt(A^2/(P^2 - E))








3 0
3 years ago
Here is a question for you
dimaraw [331]

Answer:

3/8

Step-by-step explanation:

they simply combined the like terms (aka the x numbers in this case) so all that's left is 3/8

6 0
3 years ago
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