A=6a^2
A=6(5.5)^2
A=181.5
Hopefully I answered correctly.
Answer:
see below
Step-by-step explanation:
Every vertex moves twice as far from the center of dilation as it is in the pre-image.
Perhaps the easiest image point to find is the one at lower left. In the pre-image it is 2 units left of the center of dilation, so the image point will be 2×2 = 4 units left of the center of dilation. It will be located at (-6, -2).
Other points on the image can be found either by reference to the center of dilation, or by reference to known image points. For example, the next point clockwise is 1 left and 4 up in the pre-image, so will be 2 left and 8 up from (-6, -2) in the image. That is, the pre-image point (-5, 2) becomes image point (-8, 6). You will note that (-5, 2) is 3 left and 4 up from the center of dilation, and that (-8, 6) is 6 left and 8 up from the center of dilation (twice as far away).
The problem is asking us to isolate B. The given equation is solved for P, and we need to rearrange it for B.
First we need to square both sides. This will cancel out the square root on the right side.
P^2 = E + A^2/B^2
Next, subtract E from both sides.
P^2 - E = A^2/B^2
Next we need to get the B^2 out of the denominator. Multiply both sides by B^2.
B^2(P^2 - E) = A^2
Next divide both sides by (P^2 - E).
B^2 = A^2/(P^2 - E)
Lastly, take the square root of both sides.
B = sqrt(A^2/(P^2 - E))
Answer:
3/8
Step-by-step explanation:
they simply combined the like terms (aka the x numbers in this case) so all that's left is 3/8