7 thousands divided by what number is equal to 7 hundreds?
1 answer:
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Answer:
15 early tickets were sold and 5 regular tickets were sold.
Step-by-step explanation:
Let x be the number of early bird tickets sold and y be the number of regular tickets sold.
Total number of tickets sold = 20
Thus, we can write the equation,
Cost of early bird ticket = $10
Cost of regular tickets = $15
Total cost = $225
Thus, we can write the equation,
We solve the equation by elimination method by multiplying first equation by 10 and subtracting.
Thus, 15 early tickets were sold and 5 regular tickets were sold.
Complete Question
Grandpa and Grandma are treating their family to the movies. Matinee tickets cost $4 per child and $4 per adult. Evening tickets cost $6 per child and $8 per adult. They plan on spending no more than $80 on the matinee tickets and no more than $100 on the evening tickets. Could they take 9 children and 4 adults to both shows? Show your work. A yes or no answer is not sufficient for credit.
Answer:
Yes it is possible to take the 9 children and 4 adults to both shows
Step-by-step explanation:
From the question we are told that
The cost of the Matinee tickets for a child is z = $4
The cost of the Matinee tickets for an adult is a = $ 4
The cost of the Evening tickets for a child is k = $6
The cost of the Evening tickets for an adult is b = $8
The maximum amount to be spent on Matinee tickets is m = $80
The maximum amount to be spent on Evening tickets is e = $100
The number of child to be taken to the movies is n = 9
The number of adults to be taken to the movies is j = 4
Now the total amount of money that would be spent on Matinee tickets is mathematically evaluated as
substituting values
Now the total amount of money that would be spent on Evening ticket is mathematically evaluated as
substituting values
This implies that it is possible to take 9 children and 4 adults to both shows
given that
i.e $56 $ 80
and
i.e $ 86 $ 100
1. BC is 1+3=4 (units)
2. AD is 3+5= 8 (units)
3. Draw the altitude CH from point C, as shown in the figure.
4. Then triangle CHD is a right triangle, with hypothenuse CD, and sides HD and CH.
5.
6. AB=CD=4.47 because the trapezoid is isosceles.
7. P= BC+AD+AB+CD=4+8+4.47+4.47=20.9 (units)
2. AD is 3+5= 8 (units)
3. Draw the altitude CH from point C, as shown in the figure.
4. Then triangle CHD is a right triangle, with hypothenuse CD, and sides HD and CH.
5.
6. AB=CD=4.47 because the trapezoid is isosceles.
7. P= BC+AD+AB+CD=4+8+4.47+4.47=20.9 (units)