Boyle’s Law states that volume increases with temperature
Answer:
- d = 2; m = 2; m = 2
- d= 1; m = 1; m = 2
- d = 1; m = 1; m = 1
- d = 2; m = 1; m = 2
- d = 2; m = 1; m = 1
Explanation:
The following diagrams show five pairs of asteroids, labeled with their relative masses (M) and distances (d) between them. For example, an asteroid with M=2 has twice the mass of one with M=1 and a distance of d=2 is twice as large as a distance of d=1. Rank each pair from left to right based on the strength of the gravitational force attracting the asteroids to each other, from strongest to weakest.
- d = 2; m = 2; m = 2
- d= 1; m = 1; m = 2
- d = 1; m = 1; m = 1
- d = 2; m = 1; m = 2
- d = 2; m = 1; m = 1
Answer:
2.7 x 10^-14 m
Explanation:
E =8.8 MeV = 8.8 x 1.6 x 10^-13 J
q = 2 e = 2 x 1.6 x 10^-19 C
Q = 82 e = 82 x 1.6 x 10^-19 C
Let d be the distance of closest approach
E = k Q q / d
Where, K = 9 x 10^9 Nm^2 / C^2
d = k Q q / E
d = (9 x 10^9 x 82 x 1.6 x 10^-19 x 2 x 1.6 x 10^-19) / (8.8 x 1.6 x 0^-13)
d = 2.7 x 10^-14 m
The complete question is as follows: At 700 K, decomposes to carbon and chlorine. The Kp for the decomposition is 0.76.
Find the starting pressure of at this temperature that will produce a total pressure of 1.1 atm at equilibrium.
Answer: The starting pressure of is 0.79 atm.
Explanation:
The equation for decomposition of is as follows.
Let us assume that initial concentration of is 'a'. Hence, the initial and equilibrium concentrations will be as follows.
Initial: a 0 0
Equilibrium: (a - x) 0 2x
Total pressure = (a - x) + 2x = a + x
As it is given that the total pressure is 1.1 atm.
So, a + x = 1.1
a = 1.1 - x
Now, expression for equilibrium constant for this equation is as follows.
Hence, the value of 'a' is calculated as follows.
a + x = 1.1 atm
a = 1.1 atm - x
= 1.1 atm - 0.31 atm
= 0.79 atm
Thus, we can conclude that starting pressure of is 0.79 atm.