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Marina CMI [18]
3 years ago
6

The following diagrams show five pairs of asteroids, labeled with their relative masses (M) and distances (d) between them. For

example, an asteroid with M=2 has twice the mass of one with M=1 and a distance of d=2 is twice as large as a distance of d=1. Rank each pair from left to right based on the strength of the gravitational force attracting the asteroids to each other, from strongest to weakest.
Physics
1 answer:
serg [7]3 years ago
7 0

Answer:

- d = 2; m = 2; m = 2

- d= 1; m = 1; m = 2

- d = 1; m = 1; m = 1

- d = 2; m = 1; m = 2

- d = 2; m = 1; m = 1

Explanation:

The following diagrams show five pairs of asteroids, labeled with their relative masses (M) and distances (d) between them. For example, an asteroid with M=2 has twice the mass of one with M=1 and a distance of d=2 is twice as large as a distance of d=1. Rank each pair from left to right based on the strength of the gravitational force attracting the asteroids to each other, from strongest to weakest.

- d = 2; m = 2; m = 2

- d= 1; m = 1; m = 2

- d = 1; m = 1; m = 1

- d = 2; m = 1; m = 2

- d = 2; m = 1; m = 1

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alina1380 [7]

Answer:

58.27 N

Explanation:

the data we have is:

mass: m=22kg

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and we also know the acceleration of gravity is g=9.81m/s^2

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Vertically the forces acting on the object:

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ma_{y}=N-mg

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0=N-mg\\N=mg

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now let's analyze the horizontal forces

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and the two forces just mentioned must be opposite, thus the sum of forces in the "x" axis is:

F=ma_{x}=F-f\\ma_{x}=F-\mu mg

and we are told that the crate moves at a steady speed, thus there is no acceleration: a_{x}=0

and we get:

0=F-\mu mg\\F=\mu mg

substituting known values:

F=(0.27)(22kg)(9.81m/s^2)\\F=58.27N

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