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Alchen [17]
4 years ago
7

Answer for brainliest and mad points pllllssssssss

Physics
1 answer:
BigorU [14]4 years ago
3 0
The magnitude of the resultant momentum can be calculated using the following rule:
p = sqrt [(px)^2 + (py)^2]
px is given to be 100 kg m/sec
py is given to be 98 kg m/sec

Substitute in the above equation to calculate the magnitude of the resultant momentum as follows:
p = sqrt[(100)^2+(98)^2]
p = 140 kg m/sec
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2 years ago
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34kurt
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7 0
4 years ago
A projectile is fired with an initial speed of 100 m/s and angle of elevation 30 degrees. The projectile eventually hits the gro
zaharov [31]

Answer:

Explanation:

Given

launch velocity u=100\ m/s

Launch angle \theta =30^{\circ}

Range of Projectile R=\frac{u^2\sin 2\theta }{g}

R=\frac{100^2\times \sin (2\times30)}{9.8}

R=883.699\approx 883.7

Horizontal velocity remain same and only vertical velocity changes.

Initially  vertical  velocity is in upward direction but as soon as it reaches the ground its direction change but magnitude remain same.

u_y=100\sin (30)=50\ m/s

u_x=100\cos (30)=86.60\ m/s

u_{net}=\sqrt{(50)^2+(86.60)^2}

u_{net}=99.99\approx 100\ m/s      

7 0
3 years ago
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