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WARRIOR [948]
3 years ago
14

Anybody care to help​

Mathematics
1 answer:
SVEN [57.7K]3 years ago
7 0

Answer:

DONT THANK ME OR ANYTHING PLEASE THIS IS AN DIFF QUESTION DONT REPORT EITHER

Step-by-step explanation:

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When does a limit exist.
kykrilka [37]

Answer:

In order for a limit to exist, the function has to approach a particular value. In the case shown above, the arrows on the function indicate that the the function becomes infinitely large. Since the function doesn't approach a particular value, the limit does not exist.

Step-by-step explanation:

6 0
3 years ago
7p−9=−22 elp meh plz my dudes TwT
allochka39001 [22]

Step-by-step explanation:

  • 7p-9= -22
  • 8p=-22+9
  • 8p= -13
  • p=-13/7

<h2>stay safe healthy and happy...</h2>
8 0
3 years ago
QUESTION 3 [10 MARKS] A bakery finds that the price they can sell cakes is given by the function p = 580 − 10x where x is the nu
Harman [31]

Answer:

(a)Revenue function, R(x)=580x-x^2

Marginal Revenue function, R'(x)=580-2x

(b)Fixed cost =900 .

Marginal Cost Function=300+50x

(c)Profit,P(x)=-35x^2+280x-900

(d)x=4

Step-by-step explanation:

<u>Part A </u>

Price Function= 580 - 10x

The revenue function

R(x)=x\cdot (580-10x)\\R(x)=580x-x^2

The marginal revenue function

\dfrac{dR}{dx}= \dfrac{d}{dx}(R(x))=\dfrac{d}{dx}(580x-x^2)=580-2x\\R'(x)=580-2x

<u>Part B </u>

<u>(Fixed Cost)</u>

The total cost function of the company is given by c=(30+5x)^2

We expand the expression

(30+5x)^2=(30+5x)(30+5x)=900+300x+25x^2

Therefore, the fixed cost is 900 .

<u> Marginal Cost Function</u>

If  c=900+300x+25x^2

Marginal Cost Function, \frac{dc}{dx}= (900+300x+25x^2)'=300+50x

<u>Part C </u>

<u>Profit Function </u>

Profit=Revenue -Total cost

580x-10x^2-(900+300x+25x^2)\\580x-10x^2-900-300x-25x^2\\$Profit,P(x)=-35x^2+280x-900

<u> Part D </u>

To maximize profit, we find the derivative of the profit function, equate it to zero and solve for x.

P(x)=-35x^2+280x-900\\P'(x)=-70x+280\\-70x+280=0\\-70x=-280\\$Divide both sides by -70\\x=4

The number of cakes that maximizes profit is 4.

6 0
3 years ago
[(4096)⁰]⁻⁴ =<br> a)1/(4096)⁴<br> b)-4<br> c)4096<br> d)1
SOVA2 [1]

[(4096)⁰]⁻⁴ = (4096)⁰ = 1

OPTION D

5 0
3 years ago
What was the price yesterday?
Verdich [7]

407(1+0.26)

=407*1.26

=512.82

6 0
3 years ago
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