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Flura [38]
3 years ago
7

Is the following a function? (2,5),(-9,5), (1,8), (3,2), (-2,1)? A.yes B.no

Mathematics
2 answers:
ohaa [14]3 years ago
4 0

Answer:

Yes

Step-by-step explanation:

Phantasy [73]3 years ago
4 0
Yes sorry if wrong tho
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One year ago, Joan was five times as old as her pony. In one year's time, the sum of the ages will be 22. How old is Joan now?​
iogann1982 [59]

Answer:

22 divided 5 I would think

Step-by-step explanation:

4 0
2 years ago
Simplify: ^4square root 400/ ^4square root 5 show your work
Rainbow [258]
⁴√400 / ⁴√5 = 400^¼ / 5^¼
= (5 x 2²)² / 5^¼
= 5² x 2⁴ / 5^¼
= ⁴√5^7 x 2⁴
7 0
3 years ago
How would I do this with working ?
san4es73 [151]

You Just want to get Fahrenheit alone on one side of the equal sign. Your  teacher forgot to use parenthesis. The correct equation for Celsius to Fahrenheit is: C= \frac{5}{9} (F-32)

Which will give you a completely different answer.... F = \frac{9}{5} C + 32

****

We will solve it using what is given:

C = (5/9)F - 32

C + 32 = (5/9)F

9(C + 32) = 5F

(9/5)(C + 32) = F

** If they mark you wrong, and try to say the answer is F = (9/5)C + 32 then they shouldn't be teaching math, and you should point out the fact there are no parenthesis around the F - 32 in the given formula.  

5 0
3 years ago
Jireh flew his crop duster from the ground to an altitude of 3,500 feet. He continued to fly at that height for 20 minutes until
exis [7]

Answer: Jireh flew his crop duster from the ground to an altitude of 3,500 feet.

Step-by-step explanation:

That is an example of an increasing interval.

7 0
3 years ago
Read 2 more answers
42:28
gogolik [260]

Answer:

The statements about arcs and angles that are true in the figure are;

1) ∠EFD ≅ ∠EGD

2) \overline{ED}\cong \overline{FD}

3) mFD = 120°

Step-by-step explanation:

1) ∠ECD + ∠CEG + ∠CDG + ∠GDE = 360° (Sum of interior angle of a quadrilateral)

∠CEG = ∠CDG = 90° (Given)

∠GDE = 60° (Given)

∴ ∠ECD = 360° - (∠CEG + ∠CDG + ∠GDE)

∠ECD = 360° - (90° + 90° + 60°) = 120°

∠ECD = 2 × ∠EFD (Angle subtended is twice the angle subtended at the circumference)

120° = 2 × ∠EFD

∠EFD = 120°/2 = 60°

∠EFD ≅ ∠EGD

∠ECD = 120°

∠EGD = 60°

∴∠EGD ≠ ∠ECD

2) Given that arc mEF ≅ arc mFD

Therefore, ΔECF and ΔDCF are isosceles triangles having two sides (radii EC and CF in ΔECF and radii EF and CD in ΔDCF

∠ECF = mEF = mFD = ∠DCF (Given)

∴ ΔECF ≅ ΔDCF (Side Angle Side, SAS, rule of congruency)

\\ \overline{EF}\cong \overline{FD} (Corresponding Parts of Congruent Triangles are Congruent, CPCTC)

∠FED ≅ ∠FDE (base angles of isosceles triangle)

∠FED + ∠FDE + ∠EFD = 180° (sum of interior angles of a triangle)

∠FED + ∠FDE = 180° - ∠EFD = 180° - 60° = 120°

∠FED + ∠FDE = 120° = ∠FED + ∠FED (substitution)

2 × ∠FED  = 120°

∠FED = 120°/2 = 60° = ∠FDE

∴ ∠FED = ∠FDE = ∠EFD =  60°

ΔEFD  is an equilateral triangle as all interior angles are equal

\\ \overline{EF}\cong \overline{FD}\cong \overline{ED} (definition of equilateral triangle)

\overline{ED}\cong \overline{FD}

3) Having that ∠EFD = 60° and ∠CFE = ∠CFD (CPCTC)

Where, ∠EFD = ∠CFE + ∠CFD (Angle addition)

60° = ∠CFE + ∠CFD = ∠CFE + ∠CFE (substitution)

60° = 2 × ∠CFE

∠CFE =60°/2 = 30° = ∠CFD

\overline{CF}\cong \overline{CD} (radii of the same circle)

ΔFCD is an isosceles triangle (definition)

∠CFD ≅ ∠CDF (base angles of isosceles ΔFCD)

∠CFD + ∠CDF + ∠DCF = 180°

∠DCF = 180° - (∠CFD + ∠CDF) = 180° - (30° + 30°) = 120°

mFD = ∠DCF (definition)

mFD = 120°.

5 0
3 years ago
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