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Pavel [41]
3 years ago
7

Una mujer lleva en uno de sus cromosomas X un gen letal recesivo (l), y en el otro alelo dominante normal (L). ¿Cuál es la propo

rción de sexos que cabe esperara en la dependencia de esta mujer si se casa con un hombre normal?
Biology
1 answer:
nlexa [21]3 years ago
8 0

Question in English:

A female carries a recessive lethal gene (l) on one of her X chromosomes, and a normal dominant allele (L) on the other. What is the sex ratio to be expected in this woman's dependency if she marries a normal man?

Answer:

2/3 females

1/3 males

Explanation:

Females have two X chromosomes (XX) and males have an X and a Y chromosome (XY).

The genotype of the female is XLXl. The genotype of the male is XLY, since he is normal.

The possible genotypes are:

<u>                            XL                  Xl</u>

<u>XL</u>                     <em>XLXL             XLXl</em>

<u>Y</u>                       <em>XLY               </em><em>XlY</em>

<em />

All female offspring will be normal as they will always have one normal copy of the X chromosome from their father.

50% of the male offspring will be normal, but 50% will inherit the lethal gene from their mother.

Because the allele is lethal, that means XlY males will not be born.

That means 2/3 of the children will be females, and 1/3 will be males.

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<h3 />

Experiment      

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2) One or two cabbage leaves are placed in each glass and left there for eight hours.

3) After 8 hours, the leafs turn into the color of the colored-water in which they are placed.

<h3>Explanation</h3>

When placing cabbage leaves in the glasses, they start to absorb water from the stems.

As they absorb water to drive it to other parts of the leaf, they also absorb the pigments that are giving color to the water.

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