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Pavel [41]
3 years ago
7

Una mujer lleva en uno de sus cromosomas X un gen letal recesivo (l), y en el otro alelo dominante normal (L). ¿Cuál es la propo

rción de sexos que cabe esperara en la dependencia de esta mujer si se casa con un hombre normal?
Biology
1 answer:
nlexa [21]3 years ago
8 0

Question in English:

A female carries a recessive lethal gene (l) on one of her X chromosomes, and a normal dominant allele (L) on the other. What is the sex ratio to be expected in this woman's dependency if she marries a normal man?

Answer:

2/3 females

1/3 males

Explanation:

Females have two X chromosomes (XX) and males have an X and a Y chromosome (XY).

The genotype of the female is XLXl. The genotype of the male is XLY, since he is normal.

The possible genotypes are:

<u>                            XL                  Xl</u>

<u>XL</u>                     <em>XLXL             XLXl</em>

<u>Y</u>                       <em>XLY               </em><em>XlY</em>

<em />

All female offspring will be normal as they will always have one normal copy of the X chromosome from their father.

50% of the male offspring will be normal, but 50% will inherit the lethal gene from their mother.

Because the allele is lethal, that means XlY males will not be born.

That means 2/3 of the children will be females, and 1/3 will be males.

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