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vichka [17]
3 years ago
8

Solve the equation below for m. 3

Mathematics
1 answer:
kykrilka [37]3 years ago
6 0

Answer: 30

Step-by-step explanation:

3(0.3m + 6) + m =75

(0.3 x 3 = 0.9)

(6 x 3 = 18)

0.9m + 18 + m = 75

0.9m + m + 18 = 75

(m=1)

1.9m + 18 = 75

1.9m = 75 - 18

1.9m = 57

m = 57÷ 1.9

m = 30

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you are working as a Caterer and need 20 gallons of lemonade For an upcoming event. The bottles of lemonade you are purchasing a
kifflom [539]
20 imperial gallons = 90.9218 litres 
so i'd say you'd need to buy 91 bottles or...

20 US Liquid gallons = 75.7082 litres 
so you'd have to buy 76 bottles.
Hope this answers your question! It depends what gallon you're working from.
3 0
4 years ago
Read 2 more answers
One of the diagonals of a rhombus of perimeter 120m is 36m. Find its area and the length of the other diagonal. pls answer fastt
mash [69]

Answer: 864\ m^2,\ 24\ m

Step-by-step explanation:

Given

Perimeter of the rhombus is 120\ m

Length of one of the diagonal is d_1=36\ m

All the sides of the rhombus are equal

\Rightarrow 4a=120\\\Rightarrow a=30\ m

Area of the rhombus with side and one diagonal is

\Rightarrow \text{Area=}\dfrac{1}{2}d\sqrt{4a^2-d^2}

Insert the values

\Rightarrow \text{Area=}\dfrac{1}{2}\times 36\times \sqrt{4\cdot 30^2-36^2}\\\\\Rightarrow \text{Area= }18\sqrt{3600-1296}\\\Rightarrow \text{Area= }18\times 48\\\Rightarrow \text{Area= }864\ m^2

Area with two diagonals length can be given by

\Rightarrow \text{Area =}0.5\times d_1\times d_2 \\\text{Insert the values}\\\Rightarrow 864=36\times d_2\\\Rightarrow d_2=24\ m

Thus, the area of the rhombus is 864\ m^2 and the length of the other diagonal is 24\ m

4 0
3 years ago
Which equation represents the function graphed on the coordinate plane?
VMariaS [17]

Answer:

g(x) = |x - 1| + 3

Step-by-step explanation:

7 0
3 years ago
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If a triangle has sides that are 21 and 6 what is the range for third side x?
VikaD [51]

Answer:

15<x<27

Step-by-step explanation:

Rule for the sides of a triangle:

The sum of the two smallest sides of a triangle must be greater than the biggest side.

In this question:

Sides of 6, 21 and x. We have to find the range for x.

If 21 is the largest side:

Two smallest are 6 and x.

x + 6 > 21

x > 21 - 6

x > 15

If x is the largest side:

Two smallest and 6 and 21. So

21 + 6 > x

27 > x

x < 27

Then

x has to be greater than 15 and smaller than 27. So the answer is:

15<x<27

8 0
3 years ago
11) Find:<br> (i) 36% of 400<br> (ii) 16% of 32
maxonik [38]

Hey there!

Question #1.

36% of 400

= 36% * 400

= 36/100 * 400/1

= 36 ÷ 2 / 100 ÷ 2 * 400/1

= 18/50 * 400/1

= 18 ÷ 2 / 50 ÷ 2 * 400/1

= 9 / 25 * 400/1

= 9(400) / 25(1)

= 3,600 / 25

= 3,600 ÷ 25

= 144


Therefore, the answer should be: 144

Question #2.
16% of 32

= 16% * 32

= 16/100 * 32/1

= 16 ÷ 2 / 100 ÷ 2 * 32/1

= 8 / 50 * 32/1

= 8 ÷ 2 / 50 ÷ 2 * 32/1

= 4 / 25 * 32/1

= 4(32) / 25(1)

= 128 / 25

≈ 5.12

≈ 5 3/25


Therefore, the answer should be:

• 128/25

• 5.12
• 5 3/25


(Either of those should work because they are equivalent or equal to each other!)



Good luck on your assignment & enjoy your day!



~Amphitrite1040:)

6 0
2 years ago
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