1. Find the greatest common factor (GCF)
What is the largest number that divides evenly into 3bk^2, -9bk, and 6b?
It is 3.
What is the highest degree of b that divides evenly into 3bk^2, -9bk, and 6b?
It is b.
What is the highest degree of k that divides evenly into 3bk^2, -9bk, and 6b?
It is 1, since k is not in every term.
Multiplying the results above,
The GCF is 3b
2. Factor out the GCF (Write the GCF first. Then, in parentheses, divide each term by the GCF).
3b(3bk^2/3b + -9bk/3b + 6b/3b)
3. Simplify each term in the parentheses
-3b(k^2-3k+2)
4. Factor k^2-3k+2
Ask: Which two numbers add up to -3 and multiply to 2?
-2 and -1
Rewrite the expression using the above
(k-2)(k-1)
-3b(k-2)(k-1)
Your answer is B, have a nice day :D
Y=3 is your answer. sorry for the sloppy writing
A. 
To find greater than or smaller than relation, we multiply the terms like (numerator of L.H.S with denominator of R.H.S and put the value on the left side. Then multiply the denominator of L.H.S with numerator of R.H.S and put the value on right side. Now compare the digits.)
So, solving A, we get 810<209 ... This is false
B. 
= 238>589 ..... This is false
C. 
= 496>780 .... This is false
D. 
= 420<660 ..... This is true
Hence, option D is true.
X=4, you need to add 6 to both sides which then your equation would be x/4=1. You then multiply both sides by 4. Then you are left with x=1. Use symbolab!!!
