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3 years ago

Antoine and Tess have a disagreement over how to compute a 15% gratuity on $46.00.

Mathematics

2 answers:

lana66690 [7]3 years ago

6 0

Answer:

Step-by-step explanation:

Gnom [1K]3 years ago

3 0

Answer:

B-“Tess, you found 20% of the number because you added 10% and 10%. You need to add 10% to One-half of 10%. Add $4.60 and $2.30 to get $6.90, which is the 15% gratuity.”

Step-by-step explanation:

got it rigt on edge 2021.

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A researcher selects a random sample of size n from a population and uses the collected data to compute a 95% confidence interva

Karo-lina-s [1.5K]

Answer:

I wish I know the answer

Step-by-step explanation:

lemme try again

7 0

3 years ago

Rearrange the formula A = \pi r ^ ( 2) for r

tatyana61 [14]

Consider re-writing this formula as "A = pi*r^2." The backslash symbol "\" is unnecessary.

If A = pi*r^2, and we wish to solve for r, then divide both sides by pi:

A/pi = r^2

Taking the square root of both sides, sqrt(A/pi) = r (r must be positive in this situation).

3 0

3 years ago

One hundred items are simultaneously put on a life test. Suppose the lifetimes

romanna [79]

Answer:

a) $\mathrm{E}[\mathrm{T}]=\sum_{\mathrm{H}}^{5} \frac{200}{101-i}$

b) $\mathrm{Var}[\mathrm{T}]=\sum_{k=1}^{5} \frac{(200)^{2}}{(101-i)^{2}}$

Step-by-step explanation:

Given:

The lifetimes of the individual items are independent exponential random variables.

Mean = 200 hours.

Assume, Ti be the time between ( $i-1$ )st and the $ith$ failures. Then, the $T_{i}$ are independent with $\mathrm{T}_{\mathrm{i}}$ being exponential with rate $\frac{(101-i)}{200} .$

Therefore,

a) $E[T]=\sum_{i=1}^{5} E\left[\tau_{i}\right]$

$=\sum_{i=1}^{5} \frac{200}{101-i}$

$\therefore \mathrm{E}[\mathrm{T}]=\sum_{\mathrm{H}}^{5} \frac{200}{101-i}$

$b)$

The variance is given by, $\mathrm{Var}[\mathrm{T}]=\sum_{i=1}^{5} \mathrm{Var}[T]$

$\therefore \mathrm{Var}[\mathrm{T}]=\sum_{k=1}^{5} \frac{(200)^{2}}{(101-i)^{2}}$

7 0

3 years ago

Five times the sum of a number and 6 is 48

MissTica

5(n+6)=48

5n+30=48

5n=18

n=18/5

4 0

3 years ago

Find the value of x shown below

irakobra [83]

Angles opposite to the equal sides of an isosceles triangle are equal, so the third angle in this triangle is also 61. Now, you know all the angles in the triangle, you can use the Triangle Sum Theorem, which says that all the angles in a triangle add up to 180.

x + 61 + 61 = 180

x + 122 = 180

x = 58

Hope this helped!

7 0

3 years ago