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Vinil7 [7]
3 years ago
11

Find the slope of the line passing through j(0,5) and k(-1,2)

Mathematics
1 answer:
Oliga [24]3 years ago
6 0

Answer:

3

the equation to find slope is y1-y2 / x1-x2

5-2 / 0- (-1)

3/1

3

Step-by-step explanation:

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NO LINKS!!!<br><br>14. Consider the table​
iVinArrow [24]

Answer:

(a) rate of change = 8

(b) Function: y = 8x

(c) Domain: 0 ≤ x ≤ 2

    Range: 0 ≤ y ≤ 16

Explanation:

Looks like a inverse variation sequence.

Inverse Variation formula: y = k(x)

Take two points: (1, 8), (2, 16)

Find the value of k which is constant also considered as <u>rate of change</u>.

<u>Insert values</u>:

  • 8 = k(1)
  • k = 8

===========

  • 16 = k(2)
  • k = 8

Equation: y = 8x

Domain lies in the x axis, Range lies in the y axis.

  • Here domain: 0 ≤ x ≤ 2
  • Here range: 0 ≤ y ≤ 16
5 0
1 year ago
Read 2 more answers
If an angle is three times of its supplement, find the angle​
zavuch27 [327]

Answer:

<h2>135° angle</h2>

Let the angle be x it's supplement = (180-x)

x = 3 (180-x)

⇒x=540−3x

⇒4x=540⇒x=135°

Step-by-step explanation:

Hope it is helpful....

5 0
3 years ago
PLEASE HELP OUT!!! im super lost.
Alex73 [517]

Just replace X with the given value.

X = -3

f(-3) = 5 -  (-3)

f(-3) = 5 +3

f(-3) = 8

3 0
3 years ago
Confirm that f and g are inverses by showing that f(g(x)) = x and g(f(x)) = x.
charle [14.2K]

ANSWER

See below

EXPLANATION

Given

f(x) =  \frac{ {x}- 9 }{x + 5}

and

g(x) =   \frac{ - 5x - 9}{x - 1}

(f \circ \: g)(x)=  \frac{ (\frac{ - 5x - 9}{x - 1})- 9 }{(\frac{ - 5x - 9}{x - 1} )+ 5}

(f \circ \: g)(x)=  \frac{ \frac{ - 5x - 9 - 9(x - 1)}{x - 1}}{\frac{ - 5x - 9 + 5(x - 1)}{x - 1} }

Expand:

(f \circ \: g)(x)=  \frac{ \frac{ - 5x - 9 - 9x  + 9}{x - 1}}{\frac{ - 5x - 9 + 5x - 5}{x - 1} }

(f \circ \: g)(x)=  \frac{ \frac{ - 5x - 9x  + 9 - 9}{x - 1}}{\frac{ - 5x + 5x - 5 - 9}{x - 1} }

(f \circ \: g)(x)=  \frac{ \frac{ - 14x }{x - 1}}{\frac{ -14}{x - 1} }

Since the denominators are the same, they will cancel out,

(f \circ \: g)(x)= \frac{ - 14x}{ - 14}  = x

8 0
3 years ago
Express , twelve times a number minus six is less than or equal to
xenn [34]

Answer:

12x - 6 ≤ - 18

Step-by-step explanation:

We will call "a number" x so

Twelve times a number would be:

12x

Then minus 6

12x - 6

Now we add the less than or equal to sign.

12x - 6 ≤

This is equal to negative eighteen, so:

12x - 6 ≤ - 18

As a bonus we can also solve for x.

12x - 6 = - 18    Add 6 to each side.

12x - 6 + 6 = -18 + 6

12x = -18 + 6

12x = -12  Divide each side by 12

12x/12 = -12/12

x = -12/12

x = -1

So we can say when x ≤ -1 Then 12x - 6 ≤ -18

3 0
3 years ago
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