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3 years ago

Figure PQRS is shown below.

Mathematics

2 answers:

Gwar [14]3 years ago

5 0

Answer:

parallelogram, rectangle, rhombus

Step-by-step explanation:

have a wonderful day

Pepsi [2]3 years ago

4 0

Answer:

rhombus

I hope I helps you

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A line that passes through the point (x,y), with a y-intercept of b and a slope of m, can be represented by the equation y = mx

tester [92]

Answer:

b=-18

Step-by-step explanation:

If a line that passes through the point $P(x_o,y_o)$ and it has slope $m$ , the equation of the line is:

$y-y_o=m(x-x_o)~=>y=mx+y_o-mx_o~=>b=y_o-mx_o\\\\b=-6-4(3)=-18$

4 0

3 years ago

What multiplies to 24 but adds to 23

laiz [17]

1 and negative 24 is the answer

4 0

3 years ago

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A random variable x follows a normal distribution with mean d and standard deviation o=2. It is known that x is less than 5 abou

Vaselesa [24]

Answer:

The mean of this distribution is approximately 3.96.

Step-by-step explanation:

Here's how to solve this problem using a normal distribution table.

Let $z$ be the

$\displaystyle z = \frac{x - \mu}{\sigma}$ .

In this question, $x = 5$ and $\sigma = 2$ . The equation becomes

$\displaystyle z = \frac{5 - \mu}{2}$ .

To solve for $\mu$ , the mean of this distribution, the only thing that needs to be found is the value of $z$ . Since

The problem stated that $P(X \le 5) = 69.85\% = 0.6985$ . Hence, $P(Z \le z) = 0.6985$ .

The problem is that the normal distribution tables list only the value of $P(0 \le Z \le z)$ for $z \ge 0$ . To estimate $z$ from $P(Z \le z) = 0.6985$ , it would be necessary to find the appropriate

Since $P(Z \le z) = 0.6985$ and is greater than $P(Z \le 0) = 0.50$ , $z > 0$ . As a result, $P(Z \le z)$ can be written as the sum of $P(Z < 0)$ and $P(0 \le Z \le z)$ . Besides, $P(Z < 0) = P(Z \le 0) = 0.50$ . As a result:

$\begin{aligned}&P(Z \le z)\\ &= P(Z < 0) + P(0 \le Z \le z) \\ &= 0.50 + P(0 \le Z \le z)\end{aligned}$ .

Therefore:

$\begin{aligned}&P(0 \le Z \le z) \\ &= P(Z \le z) - 0.50 \\&= 0.6985 - 0.50 \\&=0.1985 \end{aligned}$ .

Lookup $0.1985$ on a normal distribution table. The corresponding $z$ -score is $0.52$ . (In other words, $P(0 \le Z \le 0.52) = 0.1985$ .)

Given that

$z = 0.52$ ,
$x =5$ , and
$\sigma = 2$ ,

Solve the equation $\displaystyle z = \frac{x - \mu}{\sigma}$ for the mean, $\mu$ :

$\displaystyle 0.52 = \frac{5 - \mu}{2}$ .

$\mu = 5 - 2 \times 0.52 = 3.96$ .

3 0

3 years ago

What is the answer to the picture

LekaFEV [45]

Answer:

46.6

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Solve 4(2a-1) = -10(a-5)

densk [106]

Firstly, you've got to expand the brackets, this becomes;
8a-4= -10a+ 50
You've then got to eliminate the -10a and you do this by adding 10a to both sides,
This then becomes 18a-4=50
You've then got to add 4, to eliminate this, which then becomes 18a=54
You've then got to divide both sides by 18, and this becomes 3.
Therefor, a=3
Hope this helps :)

4 0

3 years ago

Read 2 more answers