<h3>
Answer: Choice D. (6,12)</h3>
Explanation:
The translation
tells us to add 1 to the x coordinate and subtract 1 from the y coordinate.
For point R(1,5) we'll arrive at R'(2,4) after applying that translation or shifting mentioned. We have moved the point 1 unit to the right and 1 unit down.
Now apply the dilation with a scale factor of 3, centered at the origin. Basically it means we triple each coordinate. We'll go from R'(2,4) to R''(6,12)
Answer:
Third option: 5.48
Step-by-step explanation:
Given the quadratic model that represents the approximate height in meters of the ball
. the time in seconds x, when the ball is 50 meters from the ground can be calculated by substituting
and solving for x.
Then:

Subtract 200 from both sides:

Divide both sides by -5:

Apply square root to both sides:

The ball is 50 meters from the ground after about 5.48 seconds.
Answer:
2
Step-by-step explanation:
what you do is -4(2)^-2 which is -1
then you do 3(5)^0 which is 3
then you add it together and it is 2
I think the correct answer from the choices listed above is the first option. The statement that is true for every rotation would be that the image and pre-image are congruent. A<span>ll the rest deals with changing the rotated shape not a constant. Hope this helps.</span>
270(pi/180)=3pi/2=theta
theta*radius=arc length
(3pi/2)(14)=65.9734 yds