A.) For the Junior Varsity Team, mean would be the appropriate measure of center since the data is <span>symmetric or well-proportioned while we should use standard deviation for getting the measure of spread since it also measures the center and how far the values are from the mean.
b.) For the Varsity Team, the median would be the appropriate measure of the center since the data is skewed left and not evenly distributed so median could be used since it does not account for outliers while we use IQR or interquartile range in measuring the spread of data since IQR does not account for the data that is skewed. </span>
Answer:
1/4 = (5n)/(n +95)
Step-by-step explanation:
If all the numbers referred to are the same number, we can use n to represent it. Then, "the ratio of a number and 4 times that number" is n/(4n) = 1/4. "The ratio of 5 times the number and 95 more than the number" is (5n)/(n+95)
The equation for the problem can be written ...
1/4 = (5n)/(95+n)
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If you're a purist, you might leave the factors of "a number" in the first raio and write it ...
n/(4n) = (5n)/(95+n)
Solving this gets you to a quadratic form that has the extraneous solution n=0.
