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Yanka [14]
3 years ago
15

What do the magnets in a computer hard drive and in the strip on a credit

Physics
1 answer:
Sonja [21]3 years ago
5 0

Answer:

they store information

Explanation:

Information are encoded on the magnetic part of a hard drive and the strip of a credit card.

  • On the drive, series of magnetic fields are used to encode information.
  • The data is stored in form of zeros and ones.
  • A credit card has a magnetic strip where information is encoded.
  • The stripe provides a readability function for electronic devices.
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An air track car with a mass of 0.75 kg and a velocity of 8.5 m/s to the right collides elastically with a 0.65kg car moving to
Sunny_sXe [5.5K]
We can do this with the conservation of momentum. The fact it is elastic means no KE is lost so we don't have to worry about the loss due to sound energy etc.

Firstly, let's calculate the momentum of both objects using p=mv:

Object 1:
p = 0.75 x 8.5 = 6.375 kgm/s

Object 2 (we will make this one negative as it is travelling in the opposite direction):
p = 0.65 x -(7.2) = -4.68 kgm/s

Based on this we know that the momentum is going to be in the direction of object one, and will be 6.375-4.68=1.695 kgm/s

Substituting this into p=mv again:

1.695 = (0.75+0.65) x v
Note I assume here the objects stick together, it doesn't specify - it should!

1.695 = 1.4v
v=1.695/1.4 = 1.2 m/s to the right (to 2sf)
8 0
3 years ago
The position of a charge in an electric field gives it _____electric
kykrilka [37]

Answer:

The space surrounding a charged object is affected by the presence of the charge; an electric field is established in that space. A charged object creates an electric field - an alteration of the space or field in the region that surrounds it. Other charges in that field would feel the unusual alteration of the space.

Explanation:

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3 years ago
Can somebody help me with this quiz please
mezya [45]
Sure what do u need help with
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Calculate the de broglie wavelength (in picometers) of a hydrogen atom traveling at 440 m/s.
Aleonysh [2.5K]

De broglie wavelength, \lambda = \frac{h}{mv}, where h is the Planck's constant,  m is the mass and v is the velocity.

h = 6.63*10^{-34}

Mass of hydrogen atom,  m = 1.67*10^{-27}kg

v = 440 m/s

Substituting

   Wavelength \lambda = \frac{h}{mv} = \frac{6.63*10^{-34}}{1.67*10^{-27}*440} = 0.902 *10^{-9}m = 902 *10^{-12}m

1 pm = 10^{-12}m\\ \\ So , \lambda =902 pm

So  the de broglie wavelength (in picometers) of a hydrogen atom traveling at 440 m/s is 902 pm

7 0
3 years ago
How much energy must be removed from a 450 g block of ice to cool it from 0∘c to -20 ∘c?
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<span>The energy removed from a 450 g block of ice can only be done with a few options: a colder freezing facility, liquid nitrogen, or stopping the energy at all and adding dry ice for a brief period. The 450 g block should loose heat energy faster in a thermostat set at -20 degrees just to maintain the ice formation.</span>
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