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snow_tiger [21]
3 years ago
7

Which of the following is a characteristic of active galaxies? A. They generally exhibit no signs of explosive activity. B. Thei

r energy emission cannot be explained as the accumulated emission of their stars. C. They are generally less luminous than normal galaxies. D. Their energy output is steady in time.
Physics
1 answer:
Virty [35]3 years ago
5 0

Answer:

The correct option is B

Explanation:

Active galaxies are characterized by a small core of emission at the center which is usually brighter than the rest of the galaxy. The energy emitted from active galaxy is way more than that emitted from normal galaxy. As compared to normal galaxy where it's energy emission is thought to be the sum of the emission from each star found in the galaxy, this is not true or the same in active galaxy. <u>There (active galaxy) huge energy emission cannot be explained as the sum of the emission of their stars</u>.

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1. In Bohr's model of the atom, where are the electrons and protons located? (1 point)
r-ruslan [8.4K]
Well, it's really dangerous to try and visualize physical models for things
of this size.  But if you must, then it's something like this:

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-- The electrons live all around the nucleus, in a space far from it. 
A description of the relative sizes that I read more than 60 years ago
and always stuck with me goes like this:   The nucleus in the middle
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This also tells us that matter is mostly empty space ! 

-- In Bohr's model of the atom, he described the whole thing very much
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We learned later that it's impossible to talk about things like "how big is
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This is NOT because we don't have good enough technology yet to
zoom in on the electrons, and at some time in the future we'll be able
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Weird ?     Hard to understand ?     You said it !

BTW ... the answer to the question is ' A ' .
5 0
3 years ago
A large truck of mass 4M is traveling at a speed of V when it collides with a small car of mass M that is at rest. The truck and
Bond [772]

Answer: (a)

Explanation:

Given

Mass of large truck is 4M with velocity V

Mass of small car is M which is at rest

After the collision car and truck stick together

Conserving momentum

\Rightarrow 4MV+M(0)=5M\times V_f\\\\\Rightarrow V_f=\dfrac{4}{5}V

For elastic collision, the velocity of the center of mass remains the same as the momentum is conserved and there is no acceleration involved.

So, for elastic collision velocity V_f_2=\frac{4}{5}V

3 0
3 years ago
The average threshold of dark-adapted (scotopic) vision is 4.00 10-11 W/m2 at a central wavelength of 500 nm. If light with this
Studentka2010 [4]

Answer:

E = h f = h c / λ     energy of single photon

n E = 4.00E-11 W/m^2       energy required for visibility

n h c / λ = 4.00E-11          number of photons required for visibility (per square meter)

n = 4.00E-11 * 5.00E-7 / (6.63E-34 * 3.00E8)

n = 20.0E-18 / 19.9 E-26 = 1.00E8

100 million photons would be required on 1 m^2 to create visibility

a / A = π * (3.6E-3)^2 / 1 = 4.07E-5     fraction of area available

4.07E-5 * 1.00E8 = 4.07E3  photons required    

           

8 0
2 years ago
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