<h3><u>Question</u><u>:</u></h3>
<u>The difference between a 2-digit number and the number formed by reversing its digits is 45. If the sum of the digits of the original number is 13, then find the number. </u>
<h3><u>Statement</u><u>:</u></h3>
<u>The difference between a 2-digit number and the number formed by reversing its digits is 45. </u><u>T</u><u>he sum of the digits of the original number is 13</u><u>.</u>
<h3><u>Solution:</u></h3>
- Let one of the digit of the original number be x.
- So, the other digit = (13-x)
- Therefore, the two digit number = 10(13-x) + x = 130-10x+x = 130-9x
- The number obtained after interchanging the digits is 10x+(13-x) =9x+13
- Therefore, by the problem
130-9x-(9x+13) = 45
or, 130-9x- 9x-13 = 45
or, -18x = 45-130+13
or, -18x= -72
or, x = 72/18 = 4
or, x = 4
- So, the original number = 130-9x = 130 -9(4) = 130 - 36 = 94
<h3>Answer:</h3>
The number is 94.
I think the answer you have given isn't right. The answer should be 94.
Answer:297.00
Step-by-step explanation:
There's 2 total decimal places in both numbers.
Ignore the decimal places and complete the multiplication as if operating on two integers.
3 6
× 8 2 5
+ 1 8 0
+ 7 2
+ 2 8 8
= 2 9 7 0 0Rewrite the product with 2 total decimal places.
Answer = 297.00
Therefore:
36 × 8.25 = 297.00
Answer:y=1
Step-by-step explanation:
Answer:
Step-by-step explanation:
In order to find the side mentioned (IJ), we need to use SOH CAH TOA.
SOH CAH TOA is an acronym to help us remember what sin, cos, and tan mean. It stands for:
Sin = Opposite / Hypotenuse
Cosine = Adjacent / Hypotenuse
Tan = Opposite / Adjacent
Since we know the measure of angle K (42) and we know one of the sides, we can use this to find the missing length.
Since the side given to us is the hypotenuse, and we're looking for the side opposite of the angle (IJ), the only possible one to use would be SIN as it includes Opposite and Hypotenuse.
Our equation is now this: 
Let's now solve for x.
Therefore, the length of IJ will be around 2.01.
Hope this helped!
The sum of 2a and 3b:
2a + 3b
