Help please I really need help

Question is in png pls some1 help !

Reika [66]

Answer:

Triangle x = 30. Pentagon x = 50

Step-by-step explanation:

For the triangle,

Find the angle which is beside x in the triangle,

let's name that angle y, so 55 + 55 + y = 180 ( we find 55 by subtracting both angles 125 from 180)

110 + y = 180

Y = 180 - 110

y = 70

Now that we have find Y, we can easily find x by subtracting 70 from 180 which would be, 70 + X = 180

x = 180 - 70

x = 30

For the pentagon,

Again find the angle which is beside x in the pentagon,

let's name that y again, 90 + 120( by subtracting 60 from 180) + 110( by subtracting 70 from 180) + 90 + y = 540

210 + 200 + y = 540

410 + y = 540

y = 540 - 410

y = 130

Now that we have find y, we can easily find x by subtracting 130 from 180 which would be, 130 + x = 180

x = 180 - 130

x = 50

Hope this helps!

7 0

3 years ago

Read 2 more answers

Can someone help me please

vovikov84 [41]

X=7

Explanation:

A triangle equals 180°, and they gave us one length already, and it says the one arm of the triangle is equal to the other so we know that the third angle is going to be the same as the second angle.

180=90+(6x+3)+(6x+3)
Combine like terms
180=96+12x
Subtract 96 from both sides
84=12x
Divide 12 by both sides
7=x

Now check it,

90+(6*7+3)+(6*7+3)
90+(45)+(45) =180

8 0

3 years ago

Helppppppppppppppp make it correct please

Taya2010 [7]

Answer:

solo me qeda

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Solving for y what is 3x-4y=-8<br> solving for y what is 3x-4y=-8

Sati [7]

Answer:

y=2+0.75x

Step-by-step explanation:

3x-4y=-8

first, subtract 3x from both sides

-4y=-8-3x

now divide by -4

y=2+0.75x

6 0

3 years ago

Hey could someone please help me with this really hard assignment is taking me forever. Thank you marking brainliest!

rewona [7]

Answer:

Exercise 1: The length of the unknown leg is 4 inches.

Exercise 3: The following straws can be used to construct the triangle: b) $3\,in$ , c) $4.5\,in$ , d) $6.5\,in$ , e) $10\,in$ , f) $13.5\,in$

Exercise 4: Possible options of this exercise: 1) (2, 4, 5), 2) (4, 5, 6), 3) (5, 6, 10), 4) (1, 2, 11), 5) (1, 4, 11), 6) (1, 10, 11)

Step-by-step explanation:

Exercise 1:

Let suppose that triangle represented in the figure is a right triangle, the length of the missing leg is determined by Pythagorean Theorem:

$y = \sqrt{l^{2}-x^{2}}$ (1)

Where:

$l$ - Hypotenuse, in inches.

$x$ - Known leg, in inches.

$y$ - Unknown leg, in inches.

If we know that $l = 11\,in$ and $x = 10\,in$ , then the length of the unknown leg is:

$y = \sqrt{21}$

Since 4 is the least whole number closest to $\sqrt{21}$ , then we conclude that the length of the unknown leg is 4 inches.

Exercise 3:

The range of possible lengths for the missing side of the triangle is represented by the following simultaneous inequality:

$x + y > l > x-y$ (2)

Where:

$x$ - Greater side, in inches.

$y$ - Lesser side, in inches.

$l$ - Missing side, in inches.

If we know that $x = 8\,in$ and $y = 6\,in$ , then we have the following range of missing sides:

$14\,in > l > 2\,in$

The following straws can be used to construct the triangle: b) $3\,in$ , c) $4.5\,in$ , d) $6.5\,in$ , e) $10\,in$ , f) $13.5\,in$

Exercise 4:

Let check each pair to determine possible constructions by means of the inequality used in Exercise 3:

(i) $x = 4\,in, y = 2\,in$

$6\,in>l>2\,in$

Possible choices: 5 inches.

(ii) $x = 5\,in, y = 2\,in$

$7\,in > l > 3\,in$

Possible choices: 4 inches, 6 inches.

(iii) $x = 6\,in, y = 2\,in$

$8\,in > l > 4\,in$

Possible choices: 5 inches, 6 inches.

(iv) $x = 10\,in, y = 2\,in$

$12\,in > l > 8\,in$

Possible choices: None.

(v) $x = 5\,in, y = 4\,in$

$9\,in > l > 1\,in$

Possible choices: 2 inches, 6 inches.

(vi) $x = 6\,in, y = 4\,in$

$10\,in > l > 2\,in$

Possible choices: 5 inches.

(vii) $x = 10\,in, y = 4\,in$

$14\,in > l > 6\,in$

Possible choices: None.

(viii) $x = 6\,in, y = 5\,in$

$11\,in > l > 1\,in$

Possible choices: 2 inches, 4 inches, 10 inches.

(ix) $x = 10\,in, y = 5\,in$

$15\,in > l > 5\,in$

Possible choices: 6 inches.

(x) $x = 10\,in, y = 6\,in$

$16\,in > l > 4\,in$

Possible choices: 5 inches.

Possible options of this exercise: 1) (2, 4, 5), 2) (4, 5, 6), 3) (5, 6, 10), 4) (1, 2, 11), 5) (1, 4, 11), 6) (1, 10, 11)

7 0

3 years ago

Read 2 more answers