All categories

3 years ago

Ocdjiowfhva;brbnhgdn

Mathematics

1 answer:

kotegsom [21]3 years ago

7 0

Answer:

yup i guess

Step-by-step explanayuption:

You might be interested in

Kurt runs diagonally across a rectangular feild u get the resr just read the image

pychu [463]

Answer:

The distance Kurt runs is 110 m

Step-by-step explanation:

All triangles add up to 180 because they make straight lines.

7 0

2 years ago

The functions f (theta) and g (theta) are sine functions, where f (0) equals g (0) equals 0.The amplitude of f (theta) is twice

777dan777 [17]

If period of $f(\theta)$ is one-half the period of $g(\theta)$ and
 $g(\theta)$ has a period of 2π, then $T_{g} =2T_{f}=2 \pi$ and $T_{f}= \pi$ .

To find the period of sine function $f(\theta)=asin(b\theta+c)$ we use the rule $T_{f}= \frac{2\pi}{b}$ .

f is sine function where f (0)=0, then c=0; with period $\pi$ , then $f(\theta)=asin 2\theta$ , because $T_{f}= \frac{2 \pi }{2} = \pi$ .

To find a we consider the condition $f( \frac{ \pi }{4} )=4$ , from where $asin2* \frac{\pi}{4} =a*sin \frac{ \pi }{2} =a=4$ .

If the amplitude of $f(\theta)$ is twice the amplitude of $g(\theta)$ , then $g(\theta)$ has a product factor twice smaller than $f(\theta)$ and while period of $g(\theta)$ is 2π and g(0)=0, we can write $g(\theta)=2sin\theta$ .

8 0

3 years ago

Here's a graph of a linear function. Write the

Savatey [412]

there is no visible graph

Step-by-step explanation:

4 0

3 years ago

How do you use equivalent fractions to compare the fractions in each pair

Alenkasestr [34]

Firstly you need to to reduce to a common denominator by multiplYing the whole fraction. This way you have to multiply 4/5 by 2 (both numerator and denominator). so 4/5 = 8/10. And now you have 8/10 and 9/10. You compare only numerators. This way you have 8/10 <9/10. Same goes for 2/3 and 5/8. Only here you need to multiply both fractions. The common denominator here is 24. So you have to multiply 2/3 by 8 and 5/8 by 3. You now have to compare 16/24 and 15/24. 16/24>15/24.

8 0

3 years ago

QUESTION B ONLY PLEASE METHOD TOO

atroni [7]

Answer:

Step-by-step explanation:

We can express 125 as 5 x 5 x 5. Therefore, the value of the cube root of 125 is 5.

$\sqrt[3]{125} = \sqrt[3]{5 \times 5 \times 5} = 5$

8 0

3 years ago