Hmm
what you do is try to eliminate 1 variable in 2 equaions first
we can elminate x's in first and 2nd equation
add first and 2nd equation
x+3y-2z=10
<u>-x-2y+z=-7 +</u>
0x+y-z=3
y-z=3
multiply 2nd equation by 3 and add to last one
-3x-6y+3z=-21
<u>3x+9y-5z=28 +</u>
0x+3y-2z=7
3y-2z=7
we now have
y-z=3
3y-2z=7
multiply first equation by -2 and add to 2nd
-2y+2z=-6
<u>3y-2z=7 +</u>
y+0z=1
y=1
now we can sub back
y-z=3
1-z=3
minus 1
-z=2
times -1
z=-2
sub baack into any equation
x+3(1)-2(-2)=10
x+3+4=10
x+7=10
minus 7
x=3
x=3
y=1
z=-2
(3,1,-2)
Answer:
a6,-3
b1,-2
c4,1
Step-by-step explanation:
The length of his territory is 12 square miles long, just divide 96 and 8, in which you get 12
560 kilometers flied in each hour
Yes all the water will fit and more because to find a volume of an object you multiple the height x length x width and in this case when all of it is calculated the base could hold 800 cm3 of water
