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2 years ago

The sum of the first 15 terms of a geometric sequence with 7 as the first term and a common ratio of -3 is __________.

Mathematics

1 answer:

Andre45 [30]2 years ago

4 0

Step-by-step explanation:

the formula for the sum of the first n terms of a geometric sequence is

Sn = s1(1 - r^n)/(1 - r)

with r being the common ratio and s1 is the first term.

so,

S15 = 7×(1 - (-3)¹⁵)/(1 - -3) = 7×(1 - -14,348,907)/4 =

= 7×14,348,908/4 = 7×3,587,227 = 25,110,589

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3 years ago

Jack took out a 6-year loan for $25,000 to purchase a boat at a 4.5% interest rate. If the interest is compounded monthly, what

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Step-by-step explanation:

To calculate the total loan payment over the course of the loan period, use the future value formula:

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2 years ago

Draw the graph of y = 3 - 1/2x

Rina8888 [55]

Answer:

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2 years ago

What is the divisor of 2/7

olga2289 [7]

Answer:

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3 years ago

Read 2 more answers

Find the derivative of f(x) = 2x^2 - 4x +3

ivolga24 [154]

Explanation

$2x^2-4x+3$

When taking derivatives of polynomials, we primarily make use of the power rule.

Power rule.

$\begin{gathered} f(x)=x^n \\ \text{then} \\ f^{\prime}(x)=nx^{n-1} \end{gathered}$

also, the derivate of a sum is the sum of the derivates

hence

$\begin{gathered} g(x)=f(x)+h(x)+\ldots z(x) \\ g^{\prime}(x)=f^{\prime}(x)+h^{\prime}(x)+\ldots.z^{\prime}(x) \end{gathered}$

Step 1

apply:

$\begin{gathered} f(x)=2x^2-4x+3 \\ f^{\prime}(x)=2\cdot2x^{2-1}-4(1)x^{1-1}+ \\ f^{\prime}(x)=4x^{}-4(1)x^0+3^0 \\ f^{\prime}(x)=4x^{}-4(1)(1) \\ f^{\prime}(x)=4z-4 \end{gathered}$

therefore, the answer is

8 0

1 year ago