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3 years ago

Can someone help explain this problem

Mathematics

1 answer:

pogonyaev3 years ago

4 0

Answer:

HK=66°

Step-by-step explanation:

Based on the diagram, we know the two sides of the arcs are equal. So we set up an equation that solves for x, then plug it back into one of the sides, and double it.

x+20=6x-45

65=5x

x=13

x+20=33

33x2=66

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Consider an experiment where two 6-sided dice are rolled. We can describe the ordered sample space as below where the first coor

agasfer [191]

Answer:

$E$ = { (4,1) , (3,2) , (2,3) , (1,4) }

$P(E)=\frac{1}{9}$

$P(F|E)=\frac{1}{4}$

Step-by-step explanation:

Let's start writing the sample space for this experiment :

$S=$ { (1,1) , (1,2) , (1,3) , (1,4) , (1,5) , (1,6) , (2,1) , (2,2) , (2,3) , (2,4) , (2,5) , (2,6) , (3,1) , (3,2) , (3,3) , (3,4) , (3,5) , (3,6) , (4,1) , (4,2) , (4,3) , (4,4) , (4,5) , (4,6) , (5,1) , (5,2) , (5,3) , (5,4) , (5,5) , (5,6) , (6,1) , (6,2) , (6,3) , (6,4) , (6,5) , (6,6) }

Let's also define the event $E$ ⇒

$E$ : '' The sum of the two dice is 5 ''

We can describe the event by listing all the favorables cases from $S$ ⇒

$E$ = { (4,1) , (3,2) , (2,3) , (1,4) }

In order to calculate $P(E)$ we are going to divide all the cases favorables to $E$ over the total cases from $S$ . We can do this because all 36 of these possible outcomes from $S$ are equally likely. ⇒

$P(E)=\frac{4}{36}=\frac{1}{9}$ ⇒

$P(E)=\frac{1}{9}$

Finally we are going to define the event $F$ ⇒

$F$ : '' The number of the first die is exactly 1 more than the number on the second die ''

⇒

$F$ = { (2,1) , (3,2) , (4,3) , (5,4) , (6,5) }

Now given two events A and B ⇒

P ( A ∩ B ) = $P(A,B)$

We define the conditional probability as

$P(A|B)=\frac{P(A,B)}{P(B)}$ with $P(B)>0$

We need to find $P(F|E)$ therefore we can apply the conditional probability equation :

$P(F|E)=\frac{P(F,E)}{P(E)}$ (I)

We calculate $P(E)=\frac{1}{9}$ at the beginning of the question. We only need $P(F,E)$ .

Looking at the sets $E$ and $F$ we find that (3,2) is the unique result which is in both sets. Therefore is 1 result over the 36 possible results. ⇒

$P(F,E)=\frac{1}{36}$

Replacing both probabilities calculated in (I) :

$P(F|E)=\frac{P(F,E)}{P(E)}=\frac{\frac{1}{36}}{\frac{1}{9}}=\frac{1}{4}=0.25$

We find out that $P(F|E)=\frac{1}{4}=0.25$

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3 years ago

Find tan(a) in the triangle<br><br> Any help will be appreciated thank you

Cerrena [4.2K]

Answer:

b 24/25

Step-by-step explanation:

SOHCAHTOA

tan is Opposite over Adjacent sides of the triangle from the perspective of angle A

so the opposite side was 24 and the adjacent side was 25

so the answer is 24/25 aka B

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3 years ago

I cant believe how bad my brother, Reuben, is at growing things. He bought a whole bunch of plants at the nursery the other day.

jeka94

Answer:

68 plants.

Step-by-step explanation:

Let x represent the number of plants that Reuben bought from the nursery.

We have been given that Reuben bought a whole bunch of plants at the nursery the other day. Right away, five died. So number of plant left would be $x-5$ .

We are also told that then our dog dug up 2/9 of them. So number of plants left after dug-up would be $\frac{2}{9}(x-5)$ .

Further a rabbit came and ate ½ of what was left. So number of plants left would be $\frac{\frac{2}{9}(x-5)}{2}=\frac{2}{9\times 2}(x-5)=\frac{1}{9}(x-5)$ .