The product of multiplying the ones digit of 59 by 853 is 7677 and the product of multiplying the tens digit of 59 by 853 is 42650 and the final product is 50327
<h3>How to determine the product of the numbers?</h3>
The numbers are given as
853 and 59
By using the standard algorithm i.e. the partial product method, we have the following equation
853 * 59 = 853 * (50 + 9)
Open the bracket
So, we have
853 * 59 = 853 * 50 + 853 * 9
Evaluate the products
So, we have
853 * 59 = 42650 + 7677
The above means that the product of multiplying the ones digit of 59 by 853 is 7677 and the product of multiplying the tens digit of 59 by 853 is 42650
Next, we evaluate the sum
853 * 59 = 50327
This means that the final product is 50327
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Answer:
the person above is right it's 4.5 units
give them the crown
Answer:
factors are any group of number or expressions which, when multiplied, produce another number or expression.
Basic example: 4 can be broken into 2 factors---2 and 2. 2 times 2 = 4
Example using an unknown:
2X + 6 = 2 * (X + 3)
In the given problem, there is no whole-number common factor. A normal convention would be to factor based on the unknown term----thus 8X is factored into 8 and X.
So: 8X + 7 = 8 ( X + 7/8 )
The following would also be correct:
8X + 7 = 4 ( 2X + 7/4 )
Step-by-step explanation:
Answer:
The coordinates of H′ are (-2,0).
Step-by-step explanation:
It is given that square EFGH stretches vertically by a factor of 2.5 with respect to the x-axis to create rectangle E′F′G′H′.
If a figure stretches vertically by a factor of 2.5 with respect to the x-axis, then the x-coordinates remains same and the points which lie on the axis are also remains the same after stretch.
It is given that the coordinates of H are (-2,0). This point lie on the x-axis, therefore it will remains the same after stretch.
Therefore the coordinates of H′ are (-2,0).
