You are given the mass of the book with an initial
height of 0.77m. You are also given the final height of the book, 2m above the
floor. The problem requires you to find the work done on the book. It is said
that work is equal to force times distance. And that force is equal to mass
times acceleration due to gravity.
W=Fd
W=mgd=mgh
W=(1.7kg)(9.8m/s^2)(2m-0.77m)
W=20.49J
<span>The work is equal to 20.49J.</span>
Answer:
D
Explanation:
You can see the 1st Law thermodynamatic, that energy flow of thermo source.
Answer:
0.37sec
Explanation:
Period of oscillation of a simple pendulum of length L is:
T
=
2
π
×
√
(L
/g)
L=length of string 0.54m
g=acceleration due to gravity
T-period
T = 2 x 3.14 x √[0.54/9.8]
T = 1.47sec
An oscillating pendulum, or anything else in nature that involves "simple harmonic" (sinusoidal) motion, spends 1/4 of its period going from zero speed to maximum speed, and another 1/4 going from maximum speed to zero speed again, etc. After four quarter-periods it is back where it started.
The ball will first have V(max) at T/4,
=>V(max) = 1.47/4 = 0.37 sec
Answer:
5.5 x 10^5 N/C
Explanation:
t = 0.001 s
Δp = - 8.8 x 10^-17 kg m /s
Force is equal to the rate of change of momentum.
F = Δp / Δt
F = (8.8 x 10^-17) / 0.001 = 8.8 x 10^-14 N
q = 1.6 x 10^-19 C
Electric field, E = F / q = (8.8 x 10^-14) / (1.6 x 10^-19)
E = 5.5 x 10^5 N/C
