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nadya68 [22]
3 years ago
6

How do I calculate the frequency of an observer

Physics
1 answer:
Alja [10]3 years ago
8 0
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Featured snippet from the web
If the observer is moving away from the source ((Figure)), the observed frequency can be found: λs=vTo−voTovTs=(v−vo)Tov(1fs)=(v−vo)(1fo)fo=fs(v−vov).
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Answer:

Explanation:

A pressure that causes the Hg column to rise 1 millimeter is called a torr. The term 1 mmHg used can replaced by the torr.

1 atm = 760 torr = 14.7 psi.

A.

120 mmHg

Psi:

760 mmHg = 14.7 psi

120 mmHg = 14.7/760 * 120

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Pa:

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B.

80 mmHg

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80 mmHg = 14.7/760 * 80

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Answer:

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A particle of mass 4.00 kg is attached to a spring with a force constant of 100 N/m. It is oscillating on a frictionless, horizo
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Solution :

Given :

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Therefore,

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When a wire loop is connected to a battery, what is produced in the loop?
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Answer:

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