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nadya68 [22]
3 years ago
6

How do I calculate the frequency of an observer

Physics
1 answer:
Alja [10]3 years ago
8 0
Search Results
Featured snippet from the web
If the observer is moving away from the source ((Figure)), the observed frequency can be found: λs=vTo−voTovTs=(v−vo)Tov(1fs)=(v−vo)(1fo)fo=fs(v−vov).
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I am primarily made of calcium. I protect and act as camouflage. I can be found as a filler in most household spices. What am I?
schepotkina [342]

Answer:

Explanation:

Bones?

Bones are primarily made of calcium. Also, they protect the body, which is pretty much obvious. They also act as camouflage.

The only but I have is, can they be found as a filler in most household?

Asides that, bones pretty much fits in to the answer.

8 0
3 years ago
8. A book is pushed a distance of 0.78 m by a force that gives the book an acceleration of 1.54 m/s². If 1.56 J of work is done
kozerog [31]

Answer:

1.29 kg

Explanation:

As we know that

W= FS

1.56 = F (0.78)

F= 1.56/0.78

F= 2 N

Now, According to the definition of Force

F= ma

then

m= F /a

m= 2 / 1.54

m = 1.29 kg

6 0
3 years ago
The sugar molecule known as sucrose is a polar molecule. Which statement BEST summarizes how sucrose will dissolve in water?
kirill [66]
I believe the answer is C

Hope this helps :)

8 0
3 years ago
5. If you walk 70 meters north in 5 minutes and 20 meters south in 15 seconds. What was the average
Tpy6a [65]

Answer:

kjfvkuzfvnv

Explanation:

3 0
3 years ago
Given the thermochemical equations X2+3Y2⟶2XY3ΔH1=−370 kJ X2+2Z2⟶2XZ2ΔH2=−120 kJ 2Y2+Z2⟶2Y2ZΔH3=−270 kJ Calculate the change in
Alchen [17]

Answer : The change in enthalpy of the reaction is, -310 kJ

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The given main reaction is,

4XY_3+7Z_2\rightarrow 6Y_2Z+4XZ_2    \Delta H=?

The intermediate balanced chemical reaction will be,

(1) X_2+3Y_2\rightarrow 2XY_3     \Delta H_1=-370kJ

(2) X_2+2Z_2\rightarrow 2XZ_2    \Delta H_2=-120kJ

(3) 2Y_2+Z_2\rightarrow 2Y_2Z    \Delta H_3=-270kJ

Now we will reverse the reaction 1 and multiply reaction 1 by 2, reaction 2 by 2 and reaction 3 by 3 then adding all the equations, we get :

(1) 4XY_3\rightarrow 2X_2+6Y_2     \Delta H_1=2\times (+370kJ)=740kJ

(2) 2X_2+4Z_2\rightarrow 4XZ_2    \Delta H_2=2\times (-120kJ)=-240kJ

(3) 6Y_2+3Z_2\rightarrow 6Y_2Z    \Delta H_3=3\times (-270kJ)=-810kJ

The expression for enthalpy of formation of CH_4 will be,

\Delta H=\Delta H_1+\Delta H_2+\Delta H_3

\Delta H=(+740kJ)+(-240kJ)+(-810kJ)

\Delta H=-310kJ

Therefore, the change in enthalpy of the reaction is, -310 kJ

5 0
3 years ago
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