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nadya68 [22]
3 years ago
6

How do I calculate the frequency of an observer

Physics
1 answer:
Alja [10]3 years ago
8 0
Search Results
Featured snippet from the web
If the observer is moving away from the source ((Figure)), the observed frequency can be found: λs=vTo−voTovTs=(v−vo)Tov(1fs)=(v−vo)(1fo)fo=fs(v−vov).
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Use what you have learned in the reading to answer the following question. The point of a compass needle points to Earth’s north
DIA [1.3K]
I would say unlimited polarity because the compass’s needle is always attracted to Earth’s north pole.

Good luck to you!
6 0
2 years ago
Joel has a mass of 50kg he is spending his firs day on skis. His friend is trying to push him across a level patch of snow. Joel
rusak2 [61]

Answer:

Because of frictional force acting in the opposite direction.

Explanation:

The force of push on the body of Joel is 60 N. The body doesn't move. This clearly means that there must be a force acting in the opposite direction that has a magnitude equal to 60 N so that the net force acting on the body of Joel is 0 and hence the body doesn't move forward.

This opposite force is the frictional force which acts between the surface of snow and Joel. The frictional force always opposes relative motion.

So, when Joel's friend pushes him, he tends move him forward. Therefore, frictional force acts in the opposite direction to oppose the motion. If the frictional force is strong enough to stop the force of push, the body won't move.

This frictional force acting on a stationary body is a variable force and has a maximum value known as limiting friction. When the force of push exceeds the limiting friction, the body just starts to move. The body won't move till the force pf push is less than or equal to limiting friction.

Thus, Joel' friend push is less than or equal to the limiting friction and therefore, Joel is not moving.

3 0
3 years ago
A car traveling at 26 m/s skids to a stop in 3 seconds. Determine the skidding distance of the car.
Aleksandr [31]

Hello!

Topic: Cinematic

For this we can say:

Initial velocity (u) = 26 m/s

Final velocity (V) = 0 m/s

Time (t) = 3 s

Distance (d) = ¿?

For calculate skidding distance, let's applicate the formula:

\boxed{d = \frac{(u+V)}{2} *t}

Replacing:

d = (\dfrac{26m/s+0m/s}{2})*3s

d =\dfrac{26m/s}{2} * 3s

d = 18m/s * 3s

d = 54\ m

The distance is <u>54 meters (m)</u>

6 0
3 years ago
Explain why increasing the mass of a car affects how the car rolls down a ramp.
Irina-Kira [14]
F = ma (force = mass x acceleration)

So the car’s mass affects the amount of force, changing how it would roll down a ramp, I think.
4 0
3 years ago
Read 2 more answers
Which direction will the box move?
Yuki888 [10]

Net force

  • F1-F2-F3
  • 5-10-20
  • 5-30
  • -25N

As it's negative the box will move left

3 0
2 years ago
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