Find the LCM of 6 and 12

ms. lorenz needs to rent a car for 3 days. she can choose from two plans. plan a costs $60 per day. plan b costs $30 per day plu

maw [93]

Answer:

distance driven < 300 miles.

Step-by-step explanation:

Plan A

She needs the car for 3 days.

1 day costs 60 dollars

3 days cost 60*3 = 180 So this is the maximum amount that she can spend

Plan B

She still needs the car for 3 days

1 day costs 20 dollars of the car does not move

3 days costs 3*20 = 60 dollars.

60 + 0.4m < 180 Subtract 60

0.4m < 180 - 60

0.4m < 120 Divide by 0.4

m < 120/ 0.4

m < 300

Answer

so she should drive less than 300 miles.

3 0

3 years ago

The number of vibrations n n per second of a nylon guitar string varies directly with the square root of the tension T T and inv

emmasim [6.3K]

Answer: $T=40.96\ KgF$

Step-by-step explanation:

We know that:

$n$ : The number of vibrations per second of the nylon guitar string.

$T$ : Tension.

$L$ : The length of the string.

Since $n$ varies directly with the square root of the $T$ and inversely with $L$ , the equation has the following form:

$n=k*\frac{\sqrt{T} }{L}$

Where "k" is the constant of variation.

Knowing that when $n=15$ and $L=0.6$ , $T=256$ , we can find the value of "k":

$n=k*\frac{\sqrt{T} }{L}\\\\L*n=k\sqrt{T}\\\\\frac{L*n}{\sqrt{T}}=k\\\\k=\frac{(0.6)(15)}{\sqrt{256}}\\\\k=0.5625$

Finally, in order to find the tension when the length is 0.3 meters and the number of vibrations is 12, you need to substitute these values and the value of "k" into $n=k*\frac{\sqrt{T} }{L}$ and solve for $T$ :

$12=(0.5625)\frac{\sqrt{T} }{0.3}\\\\\frac{12(0.3)}{(0.5625)}=\sqrt{T}\\\\(6.4)^2=T\\\\T=40.96\ KgF$

8 0

3 years ago

Solve the proportion ASAP do both promblem

lakkis [162]

8. 1/3 = 3/y

or, y= 9

11. 3/x= 6/x+8

or, 6x=3x+24

or, 3x= 24

or, x=8

Hope it helps uh.

6 0

3 years ago

Read 2 more answers

The graph of which function passes through (0,3) and has an amplitude of 3? f (x) = sine (x) + 3 f (x) = cosine (x) + 3 f (x) =

Cloud [144]

Answer:

$f(x)=3*cosine(x)$

Step-by-step explanation:

We are looking for a trigonometric function which contains the point (0, 3), and has an amplitude of 3.

We know that for a sine function $f(x)=sin(x)$ , $f(0)= 0$ ; therefore the function we a looking for cannot be a sine function because it is zero at $x=0$ .