We can check each of these using the Pythagorean Theorem,
![a^2 + b^2 = c^2](https://tex.z-dn.net/?f=a%5E2%20%2B%20b%5E2%20%3D%20c%5E2)
Option A:
![.5^2 + 1.2^2 = 1.3^2 ](https://tex.z-dn.net/?f=.5%5E2%20%2B%201.2%5E2%20%3D%201.3%5E2%0A%0A)
.25 + 1.44 = 1.691.69 = 1.69
This option works
Option B
![1^2 + 2^2 = 3^2](https://tex.z-dn.net/?f=1%5E2%20%2B%202%5E2%20%3D%203%5E2)
1 + 4 = 9
5 ≠ 9
This option does not work, but let's check the others to make sure
Option C:
![6^2 + 8^2 = 10^2](https://tex.z-dn.net/?f=6%5E2%20%2B%208%5E2%20%3D%2010%5E2)
36 + 64 = 100
100 = 100
This option works
Option D:
![3^2 + 4^2 = 5^2](https://tex.z-dn.net/?f=3%5E2%20%2B%204%5E2%20%3D%205%5E2)
9 + 16 = 25
25 = 25
This option works
So, after doing the calculations, we see that option B does not work
You can solve mean by adding up all the numbers then dividing it by the number of numbers there are.
You can solve the median by putting all of the numbers in order and then crossing off one in the beginning then crossing off one at the end. You can continue that until you get to one number in the middle.
You can solve the mode by looking for the most frequent number. That's the mode. You can remember that by looking at the MO and remember most often.
I hope this helps :-)
Answer:
2/7
Step-by-step explanation:
The quotient is ...
![\dfrac{-16}{-56}=\dfrac{2\cdot8}{7\cdot8}=\boxed{\dfrac{2}{7}}](https://tex.z-dn.net/?f=%5Cdfrac%7B-16%7D%7B-56%7D%3D%5Cdfrac%7B2%5Ccdot8%7D%7B7%5Ccdot8%7D%3D%5Cboxed%7B%5Cdfrac%7B2%7D%7B7%7D%7D)
A common factor of -8 can be cancelled from numerator and denominator.
Answer:
A, B, C, F, G
Step-by-step explanation:
The above-listed properties are inherited from a parallelogram. The properties not inherited from a parallelogram are ...
D (diagonals are angle bisectors) is inherited from a rhombus
E (congruent diagonals) is inherited from a rectangle
H (perpendicular diagonals) is inherited from a rhombus