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3 years ago

5

Ill give a brainest no cap plz actually help

1 answer:

Volgvan3 years ago

3 0

Step-by-step explanation:

Amount borrowed=400

interest rate=4%

Amount of interest after x years =0.04XxX400=$16x

Total to be paid back=400+0.04X<em>x</em>X400=400+16(1)

1) the amount of interest.if Franco pays back the loan in x=1 years is

16x1=<u>$16</u>

2) the amount of interest,if Franco pay back the loan in x=2 years is,

16x2=<u>$32</u>

3) the amount of franco will pay the lender after 2 years will be

400+(16x2)=400+32=<u>$432</u>

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A person borrows $10,000 and repays the loan at the rate of $2,400 per year. The lender charges interest of 10% per year. Assumi

omeli [17]

Answer:

a) $M(t)=24000-14000e^{t/10}$

b) It takes 5.390 years to pay off the loan.

Step-by-step explanation:

(a) The differential equation for the variation in the amount of the loan M is

$\frac{dM}{dt}=0.1M-2400$

We can express this equation as:

$\frac{dM}{dt}=0.1M-2400\\\\10\int \frac{dM}{M-24000} =\int dt\\\\10ln(M-24000)=t\\\\M-24000=Ce^{t/10}\\\\M=Ce^{t/10}+24000\\\\M(0)=Ce^{0/10}+24000=10000\\\\C+24000=10000\\\\C=-14000\\\\M(t)=24000-14000e^{t/10}$

(b) We can calculate this as M(t)=0

$M(t)=24000-14000e^{t/10}=0\\\\e^{t/10}=24000/14000=1.714\\\\t=10ln(1.714)=10* 0.5390=5.390$

It takes 5.390 years to pay off the loan.

8 0

3 years ago

The sum of the first 20 positive odd integers

svet-max [94.6K]

Answer:

$400$

Step-by-step explanation:

$We\ know\ that,\\'The\ sum\ of\ n\ no.\ positive\ odd\ integers\ is\ given\ by\ the\ formula:\\S_O=n^2\\Hence,\\Here,\\As\ n=20,\\The\ sum\ of\ the\ first\ 20\ positive\ odd\ integers=20^2=400\\$

7 0

3 years ago

53.58 is 47 percent of what?

I am Lyosha [343]

Answer:114

Sorry

Step-by-step explanation:

8 0

3 years ago

The first aircraft has 51 more seats than the second aircraft. the third aircraft has 54 fewer seats than the second aircraft. i

NikAS [45]

Let a = aircraft 1 seats

Let b = aircraft 2 seats

Let c = aircraft 3 seats

From the information given above, let's make basic equations.

$a=51+b$

$b=b$

$c=b-54$

$a+b+c=411$

We can begin to plug in values we know.

$51+b+b+b-54=411$

$3b-3=411$

$3b=414$

$b=138$

We now know that the second aircraft has 138 seats. Now we can plug in this value to find the value of the other seats. Let's start with the first aircraft.

$a=51+b$

$a=51+138$

$a=189$

We now know that the first aircraft has 189 seats. Let's now finally solve for the third aircraft.

$c=b-54$

$c=138-54$

$c=84$

Finally, we know that aircraft 3 has 84 seats. To check our work, let's make sure that each of these values add up to 411.

$a+b+c=411$

$189+138+84=411$

$411=411$

This is true, therefore the values are correct.

Aircraft 1: 189 seats

Aircraft 2: 138 seats

Aircraft 3: 84 seats

4 0

3 years ago

How to I solve 3-3X6+2= I tried PEDMAS but it did not work my answer was zero

masha68 [24]

3-3x6+2= -13 (negative 13)

6 0

3 years ago

Read 2 more answers