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Marina86 [1]
3 years ago
13

Someone please help me

Mathematics
1 answer:
MariettaO [177]3 years ago
7 0

The diagram is a "mapping diagram" that describes a function? The function pairs numbers from the set on the left with numbers from the set on the right. "Domain" refers to the numbfers on the left, where the arrows come FROM. (Some people describe this as a mapping of x to y, with x on the left and y on the right.) The answer is B.

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Answer:

m= 13/7

Step-by-step explanation:

(-5, 2) , (-12, -11)

Slope(m)

m= (y2-y1)/(x2-x1)

m= (-11 - 2)/(-12 + 5)

m= (-13)/(-7)

m= 13/7

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4 Tan A/1-Tan^4=Tan2A + Sin2A​
Eva8 [605]

tan(2<em>A</em>) + sin(2<em>A</em>) = sin(2<em>A</em>)/cos(2<em>A</em>) + sin(2<em>A</em>)

• rewrite tan = sin/cos

… = 1/cos(2<em>A</em>) (sin(2<em>A</em>) + sin(2<em>A</em>) cos(2<em>A</em>))

• expand the functions of 2<em>A</em> using the double angle identities

… = 2/(2 cos²(<em>A</em>) - 1) (sin(<em>A</em>) cos(<em>A</em>) + sin(<em>A</em>) cos(<em>A</em>) (cos²(<em>A</em>) - sin²(<em>A</em>)))

• factor out sin(<em>A</em>) cos(<em>A</em>)

… = 2 sin(<em>A</em>) cos(<em>A</em>)/(2 cos²(<em>A</em>) - 1) (1 + cos²(<em>A</em>) - sin²(<em>A</em>))

• simplify the last factor using the Pythagorean identity, 1 - sin²(<em>A</em>) = cos²(<em>A</em>)

… = 2 sin(<em>A</em>) cos(<em>A</em>)/(2 cos²(<em>A</em>) - 1) (2 cos²(<em>A</em>))

• rearrange terms in the product

… = 2 sin(<em>A</em>) cos(<em>A</em>) (2 cos²(<em>A</em>))/(2 cos²(<em>A</em>) - 1)

• combine the factors of 2 in the numerator to get 4, and divide through the rightmost product by cos²(<em>A</em>)

… = 4 sin(<em>A</em>) cos(<em>A</em>) / (2 - 1/cos²(<em>A</em>))

• rewrite cos = 1/sec, i.e. sec = 1/cos

… = 4 sin(<em>A</em>) cos(<em>A</em>) / (2 - sec²(<em>A</em>))

• divide through again by cos²(<em>A</em>)

… = (4 sin(<em>A</em>)/cos(<em>A</em>)) / (2/cos²(<em>A</em>) - sec²(<em>A</em>)/cos²(<em>A</em>))

• rewrite sin/cos = tan and 1/cos = sec

… = 4 tan(<em>A</em>) / (2 sec²(<em>A</em>) - sec⁴(<em>A</em>))

• factor out sec²(<em>A</em>) in the denominator

… = 4 tan(<em>A</em>) / (sec²(<em>A</em>) (2 - sec²(<em>A</em>)))

• rewrite using the Pythagorean identity, sec²(<em>A</em>) = 1 + tan²(<em>A</em>)

… = 4 tan(<em>A</em>) / ((1 + tan²(<em>A</em>)) (2 - (1 + tan²(<em>A</em>))))

• simplify

… = 4 tan(<em>A</em>) / ((1 + tan²(<em>A</em>)) (1 - tan²(<em>A</em>)))

• condense the denominator as the difference of squares

… = 4 tan(<em>A</em>) / (1 - tan⁴(<em>A</em>))

(Note that some of these steps are optional or can be done simultaneously)

7 0
3 years ago
Hello, I really struggle with math and I was wondering if you could help me with the following problem please? It will be much a
xz_007 [3.2K]

Answer:

x=7

Step-by-step explanation:

Simplifying

3x + 2(4 + 6x) = 113

3x + (4 * 2 + 6x * 2) = 113

3x + (8 + 12x) = 113

Reorder the terms:

8 + 3x + 12x = 113

Combine like terms: 3x + 12x = 15x

8 + 15x = 113

Solving

8 + 15x = 113

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-8' to each side of the equation.

8 + -8 + 15x = 113 + -8

Combine like terms: 8 + -8 = 0

0 + 15x = 113 + -8

15x = 113 + -8

Combine like terms: 113 + -8 = 105

15x = 105

Divide each side by '15'.

x = 7

Simplifying

x = 7

5 0
2 years ago
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