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Marina86 [1]
3 years ago
13

Someone please help me

Mathematics
1 answer:
MariettaO [177]3 years ago
7 0

The diagram is a "mapping diagram" that describes a function? The function pairs numbers from the set on the left with numbers from the set on the right. "Domain" refers to the numbfers on the left, where the arrows come FROM. (Some people describe this as a mapping of x to y, with x on the left and y on the right.) The answer is B.

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<img src="https://tex.z-dn.net/?f=%28x%5E%7B2%7D%20%2Bx-3%29%3A%20%28x%5E%7B2%7D%20-4%29%5Cgeq%201" id="TexFormula1" title="(x^{
Jlenok [28]

Answer:

x>2

Step-by-step explanation:

When given the following inequality;

(x^2+x-3):(x^2-4)\geq1

Rewrite in a fractional form so that it is easier to work with. Remember, a ratio is another way of expressing a fraction where the first term is the numerator (value over the fraction) and the second is the denominator(value under the fraction);

\frac{x^2+x-3}{x^2-4}\geq1

Now bring all of the terms to one side so that the other side is just a zero, use the idea of inverse operations to achieve this:

\frac{x^2+x-3}{x^2-4}-1\geq0

Convert the (1) to have the like denominator as the other term on the left side. Keep in mind, any term over itself is equal to (1);

\frac{x^2+x-3}{x^2-4}-\frac{x^2-4}{x^2-4}\geq0

Perform the operation on the other side distribute the negative sign and combine like terms;

\frac{(x^2+x-3)-(x^2-4)}{x^2-4}\geq0\\\\\frac{x^2+x-3-x^2+4}{x^2-4}\geq0\\\\\frac{x+1}{x^2-4}\geq0

Factor the equation so that one can find the intervales where the inequality is true;

\frac{x+1}{(x-2)(x+2)}\geq0

Solve to find the intervales when the equation is true. These intervales are the spaces between the zeros. The zeros of the inequality can be found using the zero product property (which states that any number times zero equals zero), these zeros are as follows;

-1, 2, -2

Therefore the intervales are the following, remember, the denominator cannot be zero, therefore some zeros are not included in the domain

x\leq-2\\-2

Substitute a value in these intervales to find out if the inequality is positive or negative, if it is positive then the interval is a solution, if it is negative then it is not a solution. This is because the inequality is greater than or equal to zero;

x\leq-2   -> negative

-2   -> neagtive

-1\leq x   -> neagtive

x>2   -> positive

Therefore, the solution to the inequality is the following;

x>2

6 0
2 years ago
Consider the equation 5x-2y=3. If possible, find a second linear equation to create a system of equations that has: Exactly one
nekit [7.7K]
A) One solution: 5x +2y = 0 . . . . (any line with a different slope)

b) Two solutions: not possible

c) No solutions: 5x -2y = 0 . . . . (any different line with the same slope)

d) Infinitely many solutions: 10x -4y = 6 . . . . (any other equation for the same line)
4 0
3 years ago
Read 2 more answers
Free 11 points, i know its not that much but take it.
inysia [295]

Answer:

thanks !

Step-by-step explanation:

6 0
2 years ago
3. You have decided to wallpaper your rectangular bedroom. The dimensions are 12 feet 6 inches by 10 feet 6 inches by 8 feet 0 i
Shalnov [3]

Answer:

B. 5 rolls

Step-by-step explanation:

The areas of the room, not including the ceiling, are discriminated as follows:

Longer walls: (12.5\times8)\times2=200ft^2 (6 inches equals one foot)

Shorter walls: (10.5\times8)\times2 = 168ft ^ 2 (6 inches equals one foot)

Window area: (4\times3)\times2 = 24ft ^ 2

Door area: (7\times3) = 21ft ^ 2

Area that will be effectively covered:

Total area to wallpaper: 200 + 168 -24 -21 = 323ft ^ 2

Amount of paper needed: 323\times1.1 = 355.3ft ^ 2

30in = 24in + 6in = 2ft + 0.5ft = 2.5ft. That is, the area of ​​a roll of paper is 2.5\times30 = 75ft ^ 2

Number of rolls needed:

\frac{355.3}{75} = 4.73 rolls

5 0
3 years ago
Read 2 more answers
The sum of 8 and Jose's savings is 50.
monitta

Answer:

8 + x = 50, so Jose's saving or x = 42

Hope this helps!

7 0
3 years ago
Read 2 more answers
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