The distance from Humood's house to the school is 500m
<h3>How to determine the distance from Humood's house to the school?</h3>
The given parameters are:
Humood's house is (-5,7)
The school is (3,1)
The distance between both points is calculated using
Substitute the known values in the above equation
Evaluate
d = 10
Each unit in the graph is 50m.
So, we have
Distance =10 * 50m
Evaluate the product
Distance = 500m
Hence, the distance from Humood's house to the school is 500m
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A cat is measured by millimeters, feet, inches
Answer:
<h2>124.51%</h2>
Step-by-step explanation:
In this problem, we are expected to solve for the percentage change, given the opening point and the closing point
given that the low is 4014
and the high is 9012
the formula to calculate the percentage change is given as
%change= (high-low)/low*100
substituting our given data we have
%change= (9012-4014)/4014*100
%change= (4998)/4014*100
%change= (1.2451)*100
%change= 124.51%
The total change in the stock market from the beginning of the day to the end of the day is 124.51%
The answer to this question is false that's the answer
Answer:
48%
Step-by-step explanation:
(24/50)2
= 48/100
= 48%
